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valkas [14]
3 years ago
8

What is an equation of the line that passes through the points (3,0) and (-6,-3)?

Mathematics
1 answer:
Anika [276]3 years ago
8 0
Y=1/4x-1 ?? i think.. i tried to graph it on my own on a graphing calculator so it should be correct
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The graph below represents the price of sending text messages using the services of a phone company. What is the constant of pro
Misha Larkins [42]

Answer:

8

Step-by-step explanation:

The equation is of the form

y = kx ← k is the constant of proportionality

To find k use the slope formula

k = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (2, 16) ← 2 points on the line

k = \frac{16-0}{2-0} = \frac{16}{2} = 8

4 0
3 years ago
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If you wanted to shift the graph of y= 4x + 7 down, which equation could you use?
Tresset [83]

Answer:

D

Step-by-step explanation:

4 0
3 years ago
Turning off the water while brushing your Teeth saves 350 centilliters of water. How many liters of water can you save if you tu
Blababa [14]

Answer:

1.1l

Step-by-step explanation:

350×3=1050cl

=1.05l

rounded to nearest hundredth=1.1l

3 0
3 years ago
Plz hurry!!!! thank you!!!!
Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

⇒ 1.5697 = \frac{R}{SN}

⇒ SN = 0.637 R

⇒ NP = 2×SN = 2× 0.637 R = 1.274 R

Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

⇒ tan65° = \frac{NQ}{QM}

⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

          = 0.9326 R + 0.637 R  (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

5 0
4 years ago
What is the area of the shaded sector of the circle?
finlep [7]

Answer:

Hey, where is the circle? I think you forgot to upload pic of circle.

6 0
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