Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ
Explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
Putting the values we get :
2 moles of butane releases heat = 5314.8 kJ
1 mole of butane release heat = 
Thus enthalpy of combustion per mole of butane is -2657.4 kJ
A) heating a pan of water until the water is all gone because then it would change from a liquid top a gas.
Your answer is C. Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water.
Psolution = X · PH_20
= 0.966 · 31.8 torr
= 30.7 torr