AnonymousXDX can you answer this question to

For the equilibrium

sleet_krkn [62]

Answer:

$\large \boxed{\text{0.091 atm }}$

Explanation:

The balanced equation is

I₂(g) + Br₂(g) ⇌ 2IBr(g)

Data:

Kc = 8.50 × 10⁻³

n(IBr) = 0.0600 mol

V = 1.0 L

1. Calculate [IBr]

$\text{[IBr]} = \dfrac{\text{0.0600 mol}}{\text{1.0 L}} = \text{0.0600 mol/L}$

2. Set up an ICE table.

$\begin{array}{ccccccc}\rm \text{I}_{2}& + & \text{Br}_{2} & \, \rightleftharpoons \, & \text{2IBr} & & \\0 & & 0 & &0.0600 & & \\+x & & +x & &- 2x & & \\x & & x & & 0.0600 - 2x & & \\\end{array}$

3. Calculate [I₂]

$\begin{array}{rcl}K_{\text{c}}&=&\dfrac{\text{[IBr]}^{2}} {\text{[I$_{2}$][Br]$_{2}$}}\\\\8.50 \times 10^{-2}&=&{\dfrac{(0.0600 - 2x)^{2}}{x^{2}}}& &\\\\0.2915x & = &{\dfrac{0.0600 - 2x}{x}}& &\\\\0.2915x & = &0.0600 - 2x\\\\2.2915x & = & 0.0600\\x & = & \textbf{0.026 18 mol/L}\\\end{array}\\$

4. Convert the temperature to kelvins

T = (150 + 273.15) K = 423.15 K

5. Calculate p(I₂)

$\begin{array}{rcl}\\pV & = & nRT\\p & = & cRT\\p & = & \text{0.026 18 mol} \cdot \text{L}^{-1}\times \text{0.082 06 L} \cdot \text{atm} \cdot \text{K}^{-1} \text{mol}^{-1} \times \text{423.15 K}\\& = & \textbf{0.91 atm}\\\end{array}\\\text{The partial pressure of iodine is $\large \boxed{\textbf{0.91 atm}}$}$

6 0

3 years ago

How are real gases different from ideal gases?

Anettt [7]

Real gases have small attractive and repulsive forces between particles and ideal gases do not. Real gas particles have a volume and ideal gas particles do not. Real gas particles collide inelastically loses energy with collisions and ideal gas particles collide elastically.

3 0

3 years ago

For the reaction, X + Y → A + B, ΔGo is –1324 kJ. Which one of the following statements is NOT valid concerning the reaction?

natima [27]

Answer:

c. The reaction will proceed rapidly from left to right.

Explanation:

The variation of the free Gibbs energy doesn't tell anything about the speed of reaction.

On the other hand, when ΔGo is negative: the reaction is spontaneous, thermodynamically favourable, and the products are more stable than the reactants

7 0

2 years ago

What is a good essential question for the subject molecular compounds

Mashutka [201]

Why do molecules combined into chains?

6 0

3 years ago

Calculate the number of moles and molecules of acetic acid in 22gm of it

aivan3 [116]

Answer:

0.366 moles to the nearest thousandth.

Explanation:

The molar mass of acetic acid CH3COOH = 2*12 + 4(1.008) + 2*16

= 60.03 g so the number of moles in 22 g

= 0.366.

3 0

3 years ago