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ASHA 777 [7]
3 years ago
7

Many esters have characteristic odors. Methyl salicylate exhibits a pleasant wintergreen odor. This ester can be prepared from s

alicylic acid and methanol via Fischer esterification. Which one of these reagents would you use in excess in order to drive the reaction to the product? Explain how you would isolate the ester product from the reaction mixture for full credit. (10 pts)
Chemistry
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

Methanol would be used as a reagent in excess, since it is a very low-cost solvent. For product isolation, the first thing to do is remove the methanol through a distillation process. The residue produced can be dissolved in diethyl ether. Using a NaHCO₃ solution, extraction is performed. When it separates into two phases, the product will be in the ether and the reagent in the aqueous phase. The ether can also be removed by distillation, and at the end of this process you will have the product you want.

Explanation:

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Answer:

The molar mass of the organic solid is 120.16 g/mol.

The molecular formula of an organic solid is C_4H_8O_4

Explanation:

Let the molecular mass of an organic solid be C_xH_yO_z

\Delta T_b=K_b\times m

Delta T_b=K_b\times \frac{\text{Mass of solid}}{\text{Molar mass of solid}\times \text{Mass of diphenyl  in Kg}}

where,

\Delta T_f =Elevation in boiling point = =1.5^oC

Mass of organic solid= 0.561 g

Mass of diphenyl = 24.9 g = 0.0249 kg (1 kg = 1000 g)

K_b = boiling point constant = 8.00 °C/m

m = molality

Now put all the given values in this formula, we get

1.5^oC=8.00 ^oC/m\times \frac{0.561 g}{\text{Molar mass of solid}\times 0.0249 kg}

{\text{Molar mass of solid}}=120.16 g/mol

\%=\frac{\text{Number of atoms}\times \text{mass of an atom}}{\text{molas mass of compound}}\times 100

Percentage of carbon in an organic solid = 40.0%

40\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100

x = 4.0

Percentage of hydrogen in an organic solid = 6.7%

6.7\%=\frac{y\times 1 g/mol}{120.16 g/mol}\times 100

y = 8.0  

Percentage of hydrogen in an organic solid = 6.7%

53.3\%=\frac{x\times 12 g/mol}{120.16 g/mol}\times 100

y = 4.0

The molecular formula of an organic solid is C_4H_8O_4

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Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io
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Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

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