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inna [77]
2 years ago
12

If you took a white piece of plastic to a depth of 180 m, what color would it appear?.

Physics
1 answer:
SashulF [63]2 years ago
3 0

Answer:

It would appear blue

Explanation:

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We can classify both the shovel and the garden trowel as compound machines. This is because each garden tool contains two simple
Roman55 [17]

Hello,

I believe they are a lever and a wedge.

I hope this helps!

6 0
3 years ago
Read 2 more answers
One cycle of the power dissipated by a resistor ( R = 800 Ω R=800 Ω) is given by P ( t ) = 60 W , 0 ≤ t < 5.0 s P(t)=60 W, 0≤
OLga [1]

Answer:

42.5W

Explanation:

To solve this problem we must go back to the calculations of a weighted average based on the time elapsed thus,

Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}

We need to calculate the average power dissipated by the 800\Omega resistor.

Our values are given by:

P(t)=60 W, 0\leq t

P(t)=25 W, 5.0\leq t

Aplying the values to the equation we have:

Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}

Power_{avg} = \frac{60(5-0)+25(10-5)}{(5-0)+(10-5)}

Power_{avg} = 42.5W

5 0
3 years ago
When Emma pushes a bag with a force of 27 newtons, the coefficient of kinetic friction between the bag and the floor is 0.23. Wh
vichka [17]
<span>The normal force acting on the bag by the floor is calculated using th data on the force used to push the bag and the coefficient of friction between the bag and the floor. The normal force is determined through the formula Force / kin.coeff. Substituting, 27 N / 0.23 is equal to 117. 39 N. The answer is D.</span>
6 0
3 years ago
Read 2 more answers
A single-turn circular loop of wire of radius 5.0 cm lies in a plane perpendicular to a spatially uniform magnetic field. During
Artemon [7]

Answer:

Induced EMF,\epsilon=0.0143\ volts

Explanation:

Given that,

Radius of the circular loop, r = 5 cm = 0.05 m

Time, t = 0.0548 s

Initial magnetic field, B_i=200\ mT=0.2\ T

Final magnetic field, B_f=300\ mT=0.3\ T

The expression for the induced emf is given by :

\epsilon=\dfrac{d\phi}{dt}

\phi = magnetic flux

\epsilon=\dfrac{d(BA)}{dt}

\epsilon=A\dfrac{d(B)}{dt}

\epsilon=A\dfrac{B_f-B_i}{t}

\epsilon=\pi (0.05)^2\times \dfrac{0.3-0.2}{0.0548}

\epsilon=0.0143\ volts

So, the induced emf in the loop is 0.0143 volts. Hence, this is the required solution.

5 0
3 years ago
When you drop a 4.5 kg watermelon off the Dennison building, it reaches a terminal velocity of around 35 m/s second before smash
mart [117]

Answer:

3) 52500N

Explanation:

We use the mathematical definition of impulse as follows;

Ft = mv............(1)

were F is the force experienced, t is the time of impact, m is the mass of the object and v is the velocity of impact.

Given; m = 4.5kg, v = 35m/s, t = 3 milliseconds

however, 3milliseconds=3*10^{-3}s

From equation (1);

F=\frac{mv}{t}.............(2).

Substituting all necessary values into equation (2), we obtain the following;

F=\frac{4.5*35}{3*10^{-3}}}\\\\F= \frac{157.5.5}{0.003}\\\\F=52500N

6 0
3 years ago
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