An arrow is moving at 35 m/s and travels for 5 seconds. how far did the arrow travel?

Calculate the Reynolds number for an oil gusher that shoots crude oil 25.0 m into the air through a pipe with a 0.100-m diameter

Alenkasestr [34]

Answer:

$Re=1992.24$

Explanation:

Given:

vertical height of oil coming out of pipe, $h=25\ m$

diameter of pipe, $d=0.1\ m$

length of pipe, $l=50\ m$

density of oil, $\rho = 900\ kg.m^{-3}$

viscosity of oil, $\mu=1\ Pa.s$

Now, since the oil is being shot verically upwards it will have some initial velocity and will have zero final velocity at the top.

Using the equation of motion:

$v^2=u^2-2gh$

where:

v = final velocity

u = initial velocity

Putting the respective values:

$0^2=u^2-2\times 9.8\times 25$

$u=22.136\ m.s^{-1}$

For Reynold's no. we have the relation as:

$Re=\frac{\rho.u.d}{\mu}$

$Re=\frac{900\times 22.136\times 0.1}{1}$

$Re=1992.24$

6 0

3 years ago

What is the general pattern of the planetary distances from the sun

eimsori [14]

Answer:

The Titius–Bode law (sometimes termed just Bode's law) is a hypothesis that the bodies in some orbital systems, including the Sun's, orbit at semi-major axes in a function of planetary sequence. The formula suggests that, extending outward, each planet would be approximately twice as far from the Sun as the one before.

Explanation:

8 0

4 years ago

If a 2000 N force is used to raise a piano at a rate of 10 m/s2, what is the mass of the piano?

saveliy_v [14]

Answer:

To solve this problem we will apply the principle of conservation of energy for which we have that the potential energy on a body, is equivalent to the work done on it at the given point. Therefore we will have the following equality

At the same time we know that work is equivalent to the Force applied over a given distance, so,

The potential energy is equivalent to the product between mass, gravity and height. Recall that the product of mass and gravity is equivalent to weight (The same given in the statement)

Equating,

Then,

Replacing,

Therefore the force needed to lift the piano is 600N

Explanation:

HOPE THIS HELPS!!!

3 0

3 years ago

A 3kg chunk of putty moving at a speed of 5 m/a collides with, and sticks to, a 5kg. bowling ball that is initially at REST. The

astraxan [27]

You'd have an easier time using the equation if you understood where the equation comes from.

The law here ... the major principle to remember, the key, the fundamental truth, the big cookie ... is the fact that momentum is conserved. The total momentum after they join up is the same as the total momentum before they meet.

Momentum of an object is (mass) times (speed).

Now, list all the things you know, before and after the putty meets the ball:

Before: There are two objects.
Mass of putty = 3 kg
Speed of putty = 5m/s
Momentum of putty = 3 x 5 = 15 kg-m/s.

Mass of ball = 5 kg
Speed of ball = zero
Momentum of ball = 5 x 0 = zero

Total momentum of both things = 15 kg-m/s

After: There is only one object, because they stuck together.
Mass of (putty+ball) = (3+5) = 8 kg
Speed of (putty+ball) = we don't know; that's what we have to find

Momentum of (putty+ball) = 8 x (speed)

===================================

We know that the momentum after is equal to the momentum before.

8 x (speed) = 15 kg-m/s

Divide each side by 8 :

Speed = 15 / 8 = 1.875 m/s  after they stick together.

4 0

3 years ago

A car moving due east increases its speed uniformly from 16 m/s to 32 m/s in 10.0 s. How far, in meters, did the car travel whil

omeli [17]

During the period of constant acceleration, the car's average speed is (1/2) (16 + 32) = 24 m/s. At that average speed, it covers 240 meters in 10 seconds.

3 0

4 years ago