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makkiz [27]
3 years ago
7

When Emma pushes a bag with a force of 27 newtons, the coefficient of kinetic friction between the bag and the floor is 0.23. Wh

at is the normal force acting on the bag by the floor?. A. 0.085 newtons B. 27 newtons C. 2.7 × 10^2 newtons . D. 1.2 × 10^2 newtons
Physics
2 answers:
vichka [17]3 years ago
6 0
<span>The normal force acting on the bag by the floor is calculated using th data on the force used to push the bag and the coefficient of friction between the bag and the floor. The normal force is determined through the formula Force / kin.coeff. Substituting, 27 N / 0.23 is equal to 117. 39 N. The answer is D.</span>
klemol [59]3 years ago
5 0

Answer:

the answer is D, hope this helps

Explanation:

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snow_lady [41]

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Explanation:

4 0
3 years ago
Read 2 more answers
Ford used to make a 7.0 liter engine. Calculate how many many cubic inches would be the same size engine.
Anestetic [448]

Answer : The volume of engine in cubic inches is, 427.166\text{ inch}^3

Explanation :

As we are given that the volume of engine is, 7.0 liters. Now we have to calculate the volume of engine in cubic inches.

Conversion used :

1\text{ liter}=1000cm^3

So, 7\text{ liter}=7000cm^3

1\text{ inch}=2.54cm

or,

1cm=\frac{1}{2.54}\text{ inch}

1cm^3=(\frac{1}{2.54}\text{ inch})^3

As,

1cm^3=(\frac{1}{2.54}\text{ inch})^3

So,

7000cm^3=\frac{7000cm^3}{1cm^3}\times (\frac{1}{2.54}\text{ inch})^3=427.166\text{ inch}^3

Thu, the volume of engine in cubic inches is, 427.166\text{ inch}^3

3 0
3 years ago
This parallel circuit has three resistors R1-120 ohm; R2-45 ohm: R3=360
Nina [5.8K]

Answer:

the answer is 30 Ohms. Not found in the options provided

5 0
3 years ago
A material that transmits nearly all the light in a ray because it offers little resistance to the light is
iragen [17]

A material that transmits nearly all the light that strikes it
is described as being "transparent", but that has nothing
to do with "resistance to the light", whatever that is.

Even the blackest, densest material, like wood, foil, or concrete,
has no "resistance" to light.  It simply absorbs light that enters it,
so some or all of the light that went in one side never made it to
the other side.

Transparent material absorbs very little, so almost all of the
light that goes in one side comes out the other side.

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3 years ago
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Use dimensional analysis to determine how the linear acceleration a in m/s2 of a particle traveling in a circle depends on some,
astraxan [27]

I have to say, i love this kind of problems.

So, we got the linear acceleration, as we all know, linear the acceleration its, in dimensional units:

[a]=[\frac{distance}{time^2}].

Now, we got the radius

[r] = [distance]

the angular frequency

[\omega] = \frac{1}{s}

and the mass

[m]=[mass].

Now, the acceleration doesn't have units of mass, so it can't depend on the mass of the particle.

The distance in the acceleration has exponent 1, and so does in the radius. As the radius its the only parameter that has units of distance, this means that the radius must appear with exponent 1. Lets write

a \propto r.

The time in the acceleration has exponent -2 As the angular frequency its the only parameter that has units of time, this means that the angular frequency must appear, but, the angular frequency has an exponent of -1, this means it must be squared

a \propto r \omega^2.

We are almost there. If this were any other problem, we would write:

a = A r \omega^2

where A its an dimensionless constant. Its common for this constants to appears if we need an conversion factor. If we wanted the acceleration in cm/s^2, for example. Luckily for us, the problem states that there is no dimensionless constant involved, so:

a = r \omega^2

5 0
3 years ago
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