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makkiz [27]
3 years ago
7

When Emma pushes a bag with a force of 27 newtons, the coefficient of kinetic friction between the bag and the floor is 0.23. Wh

at is the normal force acting on the bag by the floor?. A. 0.085 newtons B. 27 newtons C. 2.7 × 10^2 newtons . D. 1.2 × 10^2 newtons
Physics
2 answers:
vichka [17]3 years ago
6 0
<span>The normal force acting on the bag by the floor is calculated using th data on the force used to push the bag and the coefficient of friction between the bag and the floor. The normal force is determined through the formula Force / kin.coeff. Substituting, 27 N / 0.23 is equal to 117. 39 N. The answer is D.</span>
klemol [59]3 years ago
5 0

Answer:

the answer is D, hope this helps

Explanation:

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To find the change in centripetal acceleration, you should first look for the centripetal acceleration at the top of the hill and at the bottom of the hill.

The formula for centripetal acceleration is:
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where:
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r= radium, m

assuming the velocity does not change:

at the top of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 0.25 m
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at the bottom of the hill:
centripetal acceleration = (4.5 m/s^2) divided by 1.25 m
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to find the change in centripetal acceleration, take the difference of the two.
change in centripetal acceleration = centripetal acceleration at the top of the hill - centripetal acceleration at the bottom of the hill

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Answer:

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Explanation:

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