Sound waves....................................
Answer:
Container A and C
Explanation:
ideal gas equation gives P=nRT/V
so at constant Temperature and pressure, P=n/T
Container A and C after dividing number of moles and Volume, are found to be the same=0.0446
Answer:
n = 5 approx
Explanation:
If v be the velocity before the contact with the ground and v₁ be the velocity of bouncing back
= e ( coefficient of restitution ) = 
and
h₁ is height up-to which the ball bounces back after first bounce.
From the two equations we can write that
So on
= .00396
Taking log on both sides
- n / 2 = log .00396
n / 2 = 2.4
n = 5 approx
If a ball is if a ball is dropped from a 576ft building it would take about 8 seconds for it to hit the ground.
Answer: The minimum time between pulses (in fresh water)
= 0.3106 s
Explanation:
To calculate the speed of echoes sounds, we will use
Speed = 2x/t
Where x = distance and t = total time.
Please note that:
sound travels at 343 m/s in air. But it travels at 1,481 m/s in water (almost 4.3 times as fast as in air);
Total distance = 2 × 230 = 460m
Using speed of sound in water
1481 = 460/t
t = 460/1481
t = 0.3106
