Answer:
The speed of the riders on the Singapore Flyer is approximately 0.262 m/s
Explanation:
The dimensions of the tallest Ferris wheel in the world are;
The diameter of the Ferris wheel, D = 150 m
The tine it takes the Ferris wheel to make a full circle, T = 30 minutes = 30 min × 60 s/min = 1,800 seconds
The angular velocity of the Ferris wheel, ω = 2·π/T
The linear velocity of the Ferris wheel, v = r·ω = The speed of the riders
Where;
r = The radius of the Ferris wheel = D/2
D = 150 m
∴ r = 150 m/2 = 75 m
∴ v = r·2·π/T
∴ v = 75 m × 2 × π/(1,800 s) ≈ 0.262 m/s
The speed of the riders on the Singapore Flyer, v ≈ 0.262 m/s
Answer:
Explanation:
Magnetic field due to a moving charge
B = μ₀ / 4π x (qv x r)/r²
Given
B = .3 X 10⁻⁶ T,
r = 60 x 10⁻³ m
Putting these values in the given equation
.3 x 10⁻⁶ = 10⁻⁷ x qvsinθ /( 60 x 10⁻³)²
θ = 90 °
qv = 10.8 x 10⁻³
At point P
Sinθ = 60 / 72
r² = 72 x 72 x 10⁻⁶
B = 
= 0.17 μT
