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ahrayia [7]
3 years ago
13

Complete the sentence

Physics
1 answer:
scoray [572]3 years ago
6 0

The object is at rest.


This is due to the fact hwen two forces act upon each other on opposite sides, the movement of the object does not change due to the net force equaling 0.

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The average distance between the variable scores and the mean in a set of data is the __________. A. range B. standard deviation
ololo11 [35]
The average distance between the variable scores and the mean in a set of data is the standard deviation.

6 0
3 years ago
Read 2 more answers
. A car with a mass of 700-kg changes its speed from 10.0 m/s to 30.0 m/s in a displacement of 50.0 meters. Calculate the net fo
Nezavi [6.7K]

Answer:

5600N

Explanation:

Given parameters:

Mass of car  = 700kg

Initial velocity  = 10m/s

Final velocity  = 30m/s

Displacement  = 50m

Unknown:

Net force acting on the car  = ?

Solution:

To find the force acting on a body, it is pertinent we know the mass and acceleration.

 Force  = mass x acceleration

Now;

 Let us find the acceleration from the kinematics equations:

 v²  = u²  + 2aS

 v is the final velocity

 u is the initial velocity

 a is the acceleration

 S is the distance

  30²  = 10²  + (2 x a x 50)

 900 = 100 + 100a

      100a  = 800

           a  = 8m/s²

Therefore;

     Force  = 700 x 8  = 5600N

6 0
3 years ago
0. What is centripetal accleration?Derive relation for it​
NISA [10]

Answer:

Centripetal acceleration is defined as the property of the motion of an object, traversing a circular path. Any object that is moving in a circle and has an acceleration vector pointed towards the center of that circle is known as Centripetal acceleration. ... Centripetal means towards the center.

4 0
3 years ago
Read 2 more answers
What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a w
Delvig [45]
(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by
f_1 =  \frac{1}{2L} \sqrt{ \frac{T}{m/L} }
where
L is the wire length
T is the tension
m is the wire mass

In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
T= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }= \frac{1}{2 \cdot 10.9 m} \sqrt{ \frac{253 N}{0.0558 kg/10.9 m} }=    10.2 Hz

b) The frequency of the nth-harmonic for a standing wave in a wire is given by
f_n = n f_1
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
f_2 = 2 f_1 = 2 \cdot 10.2 Hz=20.4 Hz

c) Similarly, the third lowest frequency (third harmonic) is given by
f_3 = 3 f_1 = 3 \cdot 10.2 Hz = 30.6 Hz

8 0
3 years ago
To clearly see an image, the wavelength used must be at most 1/4 of the size of the object that is to be imaged. what frequency
LuckyWell [14K]
From the statement, the wavelength should be 1.6 cm * 1/4 = 0.4 cm. Then, we use the wave equation formula. The frequency is equal to the speed of light divided by the wavelength. First, let's use the SI units.

0.4 cm = 0.004 m

The speed of light is equal to 3 x 10^8 m/s

Frequency = 3 x 10^8 m/s ÷ 0.004 m
Frequency = 7.49 x 10^10 s^-1
5 0
3 years ago
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