Ask question

Ask question

All categories

3 years ago

15

What is the change in vapor pressure when 74.60 g fructose, C6H12O6, are added to 185.5 g water (H2O) at 298 K (vapor pressure o

f pure water at 298 K

1 answer:

Vlad1618 [11]3 years ago

3 0

Answer:

Vapor pressure of pure water: 3.1690 kPa

Explanation:

Vapor pressure is P=0.955(3.1690)=3.0263 kPa

Change in vapor pressure : 3.169-3.0263=0.142 kPa

You might be interested in

Which statement would support a merit of the Bronsted-Lowry base theory has over the Arrhenius base theory?

butalik [34]

Answer:

Explanation:

Bronsted Base is an H+ acceptor

No good answer Bronstead base does not accept hydroxide or electrons

5 0

3 years ago

Read 2 more answers

A container of argon with a volume of 22 ml has a pressure of 101.0 kPa.

Alexeev081 [22]

Answer:

The new pressure is 44.4 kPa.

Explanation:

We have,

Initial volume, $V_1=22\ ml$

Initial pressure, $P_1= 101.0\ kPa$

It is required to find the new pressure when the volume is increased to 50 ml. The relationship between pressure and volume is known as Boyle's law.

$PV=k\\\\P_1V_1=P_2V_2$

$P_2$ is final pressure

$P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{22\times 101\times 10^3}{50}\\\\P_2=44440\ Pa\\\\P_2=44.4\ kPa$

So, new pressure is 44.4 kPa.

6 0

3 years ago

What is the primary role of the United States Bureau of Counterterrorism?

zubka84 [21]

o advance counterterrorism efforts in other countries

7 0

3 years ago

Read 2 more answers

Think of a resource and predict What happens to the resource when competition for it increases

MatroZZZ [7]

Lets say foxes hunt rabbits. If their are too many foxes then they will compete for the rabbits. The rabbits get outnumbered by the amount of foxes so the foxes kill all the rabbits and the rabbits could eventually go extinct.

3 0

3 years ago

A standard backpack is approximately 30cm x 30cm x 40cm. Suppose you find a hoard of pure gold while treasure hunting in the wil

Blizzard [7]

Explanation:

The dimensions of a standard backpack is 30cm x 30cm x 40cm

The mass of an average student is 70 kg

We know that, the density of gold is 19.3 g/cm³.

Let m be the mass of the backpack. So,

$\text{density}=\dfrac{\text{mass}}{\text{volume}}\\\\m=d\times V\\\\m=19.3\ g/cm^3\times (30\times 30\times 40)\ cm^3\\\\m=694800\ g\\\\\text{or}\\\\m=694.8\ kg\approx 700\ kg$

An average student has a mass of 70 kg. If we compare the mass of student and mass of backpack, we find that the backpack is 10 times of the mass of the student.

8 0

3 years ago