Paul needs to invest $10000 at 6% interest and $30000 at 10% interest to make a total of 9% return on his $40000.
<em><u>Explanation</u></em>
Suppose, the amount of money at 6% interest is
As Paul has total $40000 to invest, so the amount of money at 10% interest will be: 
His intent is to earn 9% interest on his $40000 investment. So, the equation will be......

So, Paul needs to invest <u>$10000 at 6% interest</u> and ($40000- $10000) or <u>$30000 at 10% interest </u>to make a total of 9% return on his $40000.
The answer I got is (-6,-2) the x value is -6
percent of increase for a population that changed from 25,000 to 30,000
Increase in population = 30,000 - 25,000 = 5000
So, the increase in population is 5000
To find percent of increase , we divide the increase in population by initial population.
So percent of increase =
* 100
= 0.2 * 100
= 20 %
20% of increase for a population that changed from 25,000 to 30,000.
7 * 38 + 3*45 - 56
use order of operations
(7*38) + (3*45) - 56
266 + 135 - 56
=345