any number that doesn't have a variable can not go into a number that has variable so there would only be 1
i think its 84 miles in 7 days
Answer:
30
Step-by-step explanation:
To find the determinant of a 3x3 matrix, you can use this method. (See picture.)
Start with the first number in the top row, and block off the row and column. A 2x2 matrix will be left. Find the determinant of this 2x2 matrix, and multiply it by the number in the top row.
Repeat for the other two numbers in the top row. Add the first result, subtract the second, and add the third.
det A = -2 [(3)(-5) − (a)(0)] − 2 [(0)(-5) − (a)(0)] + b [(0)(0) − (3)(0)]
det A = -2 (3)(-5) − 0 + 0
det A = 30
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Answer:</h2>
<em>Rounded to the nearest hundredth the volume of the composite figure is:</em>
<em>1308 33 cubic millimeters</em>
<h2>
Explanation:</h2>
Hello! I wrote the complete question in a comment above. The volume of a cylinder is defined as:
While the volume of half a sphere is:
Since we have 2 half spheres, then the volume of these is the same as the volume of a sphere:
Then, the composite figure is:
The radius of the cylinder is the same of the radius of each half sphere. So:
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The correct answers are:</span><span>
(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0
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Explanation:</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.
Rational Function = g(x) = </span></span>
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Denominator = x = 0
Hence the vertical asymptote is x = 0.
(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:
Given function = g(x) = </span>
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We can write it as:
g(x) = </span>
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If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.
In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
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