Answer:
I think it's y=15x+0
Step-by-step explanation:
y=mx+b
y=15x+0
I attached a picture from desmos.
If the length of side of base is 14 inches and height is 6 inches of pyramid a then the volume of pyramid a is 12.5% of pyramid b and volume of pyramid a is 8 times bigger than volume of pyramid b.
Given the length of side of base of pyramid a is 14 inches , height of pyramid a is 6 inches and volume of pyramid b is 3136 cubic inches.
We have to determine the percentage and number of times that volume of b is bigger than volume of pyramid b.
Volume of a square pyramid=base area * height/3
Base area = Side * side
=14*14
=196 inches square.
Volume of pyramid a =196*6/3
=392 cubic inches.
Percentage=Volume of pyramid a / volume of pyramid b*100
=392/3136*100
=12.5%
Let the number of times be x.
So,
392*x=3136
x=3136/392
=8 times.
Hence the volume of pyramid b is 8 times bigger than volume of pyramid a and the percentage is 12.5%.
Learn more about volume at brainly.com/question/1972490
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puteri [66]
Answer:
96
bcs the exercise room is 70
weight room is 42
but they both include locker room
the locker room is 16
locker room calculated twice
so 70 + 42 - 16 = 96
Perimeter = (length+width) x 2
Let w units be the width of the rectangle.
Length of the rectangle = 2w
Perimeter:
(2w+w) x 2 = 60
(3w)2 = 60
6w = 60
w = 10
Area:
2(10) x 10
= 20 x 10
= 200 units
Answer:
x = 8
Step-by-step explanation:
13 - 5 = 8
x = 8
hope this helps...