1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mel-nik [20]
2 years ago
8

Approximate the distance between (2,4) and (7,2) to the nearest tenth.

Mathematics
1 answer:
mojhsa [17]2 years ago
4 0

Answer:

5,2

Step-by-step explanation:

this is the distance of these points

You might be interested in
Dafjjfdsfrdddddddd DISJFJIASJIFAJIFAIJIJASJDIASIJDJAISDJAIS
photoshop1234 [79]

Answer:

What?

Step-by-step explanation:

3 0
3 years ago
The house has a form of a rectangle with one side two and a half times as long as the other side. a Construct the expression for
Nookie1986 [14]

Answer: A=2.5x^{2}


Step-by-step explanation:

1. Let's write the following formula for calculate the area of a rectangle:

A=yx

Where y is the lenght (the longer side) and x is the width (the shorter side).

2. You know that the length is 2.5 times as long as the other side, which indicates a multiplication. Then:

y=2.5x

3. So, you must substitute y into the equation for calculate the area of the rectangle and then you must simplify.

4. Then, you obtain the following expression:

A=(2.5x)(x)\\A=2.5x^{2}


4 0
3 years ago
Find the square root by factor <br>21904 
mihalych1998 [28]
21904|2\\10952|2\\.\ 5476|2\\.\ 2738|2\\.\ 1369|37\\.\ \ \ \ 37|37\\.\ \ \ \ \ \ 1|\\\\21904=2\times2\times2\times2\times37\times37=2^4\times37^2\\\\\sqrt{21904}=\sqrt{2^4\times37^2}=\sqrt{2^4}\times\sqrt{37^2}=2^2\times37=4\times37=148



\sqrt{21904}=\sqrt{4\times5476}=2\sqrt{4\times1369}=2\times2\sqrt37\times37}=4\times37=148

8 0
3 years ago
Read 2 more answers
A cone and a sphere both have a radius of 1. If you fill the cone with liquid, and pour it into the sphere, it fits exactly. Wha
PtichkaEL [24]

Answer and Step-by-step explanation:

First, solve for the volume of the sphere, then solve for the height of the cone using the volume of the sphere (which is said to be equal to the volume of the cone) and the radius given.

<u>Volume formula of Sphere</u>

V = \frac{4}{3} \pi r^2

<u>Substitute 1 in for r</u>

\frac{4}{3} \pi (1)^2 = \frac{4}{3} \pi  = 4.189 = Volume

<u>Finding the Height of a Cone</u>

Volume formula for Cone: V = \pi r^2\frac{h}{3}

<u />

<u>Solve for </u><u><em>h</em></u>

Multiply both sides by 3, then divide by pi and r^2.

h = \frac{3V}{\pi r^2}

<u>Plug in the volume and the radius.</u>

h = \frac{3(4.189)}{\pi (1)^2}

<u>Simplify</u>

h = \frac{12.567}{\pi }

h ≈ 4

<u>4 is approximately the height.</u>

<u></u>

<u></u>

<u><em>#TeamTrees #PAW (Plant And Water)</em></u>

6 0
3 years ago
Someone help please I really need the answer fast if that’s possible!!??
ycow [4]

Answer:

no yes no i dumb

Step-by-step explanation:

5 0
3 years ago
Other questions:
  • Ursula Vanov can invest $5,000 in a 1-year CD at 3% compounded monthly or a 1-year CD compounded daily. Determine the amount at
    14·1 answer
  • What is the alt code for the division sign? 50 points
    7·2 answers
  • Determine the slopes from the given information<br><br> A line through (3,-3) and (8,4)
    15·1 answer
  • Tyrell is constructing an angle congruent to angle Q. The work he has done so far is shown below.
    8·1 answer
  • Find the degree of the monomial x^2 z^3
    6·1 answer
  • If (x+2) is a factor of 3x^2+14x+k, what is the value of k?
    13·1 answer
  • 2. A boy runs at a speed of 10m/s. How long does he take to cover a distance of 1.5 km?<br> 'D Focus
    7·1 answer
  • Your job is to sort and stack marblesfor sale. A bag contains 44 marbles, and some green. If there are 11 red marbles, what is t
    12·2 answers
  • Help now pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
    10·2 answers
  • PLEASE HELP ILL MARK BRAINLIEST AND GIVE 5 STATS AND LIKE IT PLEASE
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!