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777dan777 [17]
2 years ago
7

Question 7: Help Me Please

Mathematics
2 answers:
ehidna [41]2 years ago
7 0

Answer:

m∠UQT = 52°
m∠UTQ = 42°
x = 1

Step-by-step explanation:

∠UQT is an alternate interior angle of ∠RSQ

Therefore, ∠UQT is 52°

∠UTQ is an alternate interior angle of ∠URS

Therefore, ∠UTQ is 42°

The diagonals of a parallelogram are congruent, so 4x + 1 is 5

  • 4x + 1 = 5
  • 4x = 4
  • x = 1

-Chetan K

Romashka [77]2 years ago
4 0
  • QR||TS

QS is the intersector

  • <UQT=<QSR(Alternative interior angles)=52°

Similarly

  • <UTQ=<URS=42°

Now

Diagonals of parallelogram bisect eachother

\\ \rm\Rrightarrow 4x+1=5

\\ \rm\Rrightarrow 4x=4

\\ \rm\Rrightarrow x=1

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a)

(a, b) ∈ R if and only if everyone who has visited Web page a has also visited Web page b.

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R <em>is not anti-symmetric</em> (aRb and bRa does not imply a=b)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page a does not mean the web pages are the same.

R <em>is transitive</em> (aRb and bRc implies aRc)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page c implies that everyone who has visited Web page a has also visited Web page c.

b)

(a, b) ∈ R if and only if there are no common links found on both Web page a and Web page b.

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R <em>is symmetric </em>(aRb implies bRa)

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R <em>is not anti-symmetric</em> (aRb and bRa does not imply a=b)

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