Answer: 17.34 grams of alum will be produced if 0.9875 g of Aluminium foil was used.
Explanation: Reaction to form alum from Aluminium is given as:
We are given Aluminium to be the limiting reactant, so the formation of alum will be dependent on Aluminium because it limits the formation of product.
By stoichiometry,
2 moles of Al is producing 2 moles of Alum
Mass of 2 moles of Aluminium = (2 × 27)g/mol = 54 g/mol
Mass of 2 moles of alum = (2 × 474)g/mol = 948 g/mol
54 g/mol of aluminium will produce 948 g/mol of alum, so
Amount of Alum produced = 17.34 grams
Theoretical yield of alum = 17.34 grams.
Answer:
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<span>0.298 M
The balanced equation for the reaction is
HCl + NaOH = H2O + NaCl
So for every mole of NaOH used, one mole of HCl is neutralized. So let's determine how many moles of NaOH we used. That will simply be the volume (in liters) of solution multiplied by the molarity. So
0.0493 L * 0.151 mol/L = 0.0074443 mol
Because of that 1:1 ratio, we now know that 0.0074443 moles of HCl was in the sample. Since molarity is moles per liter, a little division will give us the molarity of the HCl solution. So
0.0074443 mol / 0.025 L = 0.297772 mol/M = 0.297772 M
Rounding to 3 significant figures gives 0.298 M.</span>
Answer:
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An Anabolic Reaction is a reaction which take and form what's in your food (in this case fatty acids) and form complex molecules.
Explanation:
In other words it is the gathering and construction of molecules using energy!
HOPE THIS HELPS!!
The answer is b hope this helped you