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Andrews [41]
3 years ago
7

What is the voltage this voltmeter is measuring? Be sure your answer has a reasonable number of decimal place

Chemistry
1 answer:
Mnenie [13.5K]3 years ago
8 0
Hi! I would say the voltage can be measured at 0.083 volts
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Which atom has the least attraction for the electrons in a bond between that atom and an atom of hydrogen?
Helga [31]

Answer:

carbon

Explanation:

tbh im not sure just guessing

8 0
3 years ago
Malik analyzed three samples to test which element was a metalloid. The table shows his results. Which element (A, B, or C) is m
11111nata11111 [884]

the answer is c :)

have a good day (good vibes only)

- sav <3

7 0
3 years ago
Read 2 more answers
Which elements have similar behavior? barium silicon aluminum strontium osmium beryllium
victus00 [196]

Answer:

Barium, strontium and beryllium, all belong to the group 2. Silicon belong to group 14. Aluminium belong to group 13 and Osmium belong to group 8. Hence, the elements which have similar behavior are Barium, strontium and beryllium.

Explanation:

hope this helps

6 0
3 years ago
30.0 grams of NaNO3 is dissolved in water to make a 5.00 L solution. What is the molarity of the solution?
Morgarella [4.7K]

Answer:

Molarity= 0.071M

Explanation:

Molar mass of NaNO3= 23+14+(16*3)=85

n= m/M = 30/85= 0.353mol

V= 5L

Applying

n= CV

0.353= C×5

Simplify

C= 0.071M

4 0
3 years ago
A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t
andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)

<u>Where:</u>

<em>μ (l): is the chemical potential of 2-propanol in solution    </em>

<em>μ° (l): is the chemical potential of pure 2-propanol   </em>

<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>

<em>T: is the temperature = 82.3 °C = 355.3 K </em>

<em>x: is the mole fraction of 2-propanol = 0.41 </em>

\mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41)

\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}

\mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1}  

Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

I hope it helps you!    

8 0
4 years ago
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