Answer:
0.0917 mol Co(CrO₄)₃
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
37.3 g Co(CrO₄)₃
<u>Step 2: Identify Conversions</u>
Molar Mass of Co - 58.93 g/mol
Molar Mass of Cr - 52.00 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Co(CrO₄)₃ - 58.93 + 3(52.00) + 12(16.00) = 406.93 g/mol
<u>Step 3: Convert</u>
<u /> = 0.091662 mol Co(CrO₄)₃
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
0.091662 mol Co(CrO₄)₃ ≈ 0.0917 mol Co(CrO₄)₃
Answer:
I think C ,correct me if I'm wrong
M = 125 g = 125/1000 kg = 0.125 kg, θ₂ = 78.0°C, θ₁ = 23.5°C , c = 0.44kJ/kg°C,
Q = mc(θ₂ - θ₁)
Q = 0.125*0.440*(78 - 23.5)
Q = 2.9975 kJ
2.9975 kJ<span> required to warm it.</span>
In chemistry, the molar mass of a chemical compound is defined as the mass of a sample of that compound divided by the amount of substance in that sample, measured in moles.
Answer: Thus the overall equation will be
Explanation:
According to Hess’s law , the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The intermediate balanced chemical reaction are:
(1)
(2)
(3)
Now adding all the equations, we get :
Thus the overall equation will be