A 25.00 ml sample of hydrochloric acid solution, HCl, is titrated with 0.0512 m NaOH solution. the volume of NaOH solution required is 21.68 ml then the molarity of the HCl solution is 0.044 M .
Calculation ,
Formula used :
...( i )
Where M is the molarity or concentration and V is the volume in ml .
concentration of hydrochloric acid solution (
) = ?
concentration of NaOH (
) = 0.0512 M
volume of hydrochloric acid solution (
) = 25.00 ml
volume of NaOH (
) = 21.68 ml
Putting the value of concentration , volume of both in equation ( i ) we get .
× 25.00 ml = 0.0512 × 21.68 ml
= 0.0512 × 21.68 ml / 25.00 ml= 0.044 M
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Answer:
2HBr(g) → H₂ (g) + Br₂ (g)
2Al + Fe₂O₃ → 2Fe + Al₂O₃
2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O
Ag + Pb₃(PO₄)₂ → No reaction
K₂CO₃ + Cal₂ → 2KI + CaCO₃
Explanation:
1st reaction:
2HBr(g) → H₂ (g) + Br₂ (g)
HBr produces hydrogen and bromine gas.
Second reaction:
2Al + Fe₂O₃ → 2Fe + Al₂O₃
Aluminium is more reactive than iron that's why it displace the iron from oxide and form aluminium oxide.
3rd reaction:
2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O
Butyne burn in the presence of oxygen and produces carbondioxide and water.
4th reaction:
Ag + Pb₃(PO₄)₂ → No reaction
Because lead is more more reactive than silver that's why silver can not displace the lead to react with (PO₄)₂ .
5th reaction:
K₂CO₃ + Cal₂ → 2KI + CaCO₃
potassium carbonate react with calcium iodide and produces calcium carbonate and potassium iodide.
The answer is;
- Real gas particles have significant volume
- Real gas particles have more complex interactions than ideal gas particles
When using the ideal gas equation (PV= nRT)particular assumptions are made. That the molecules of the gas occupy negligible space and that the molecules only interact through elastic collision. However, the molecules of real gas have a finite volume and they interact also through intermolecular forces (such as in partially-charged molecules).
<u>Given:</u>
Enthalpy change (ΔH) for SO3 decomposition = +790 kJ
Moles of SO3 = 2.1 moles
<u>To determine:</u>
Energy required when 2.1 moles of SO3 reacts
<u>Explanation:</u>
The decomposition reaction is -
2SO3(g) → 2S(s) + 3O2 (g)
Energy required when 2 moles of SO3 reacts is 790 kJ
Thus, for 2.1 moles of SO3 the energy requirement would be
= 2.1 moles SO3 * 790 kJ/2 moles SO3 = 829.5 kJ
Ans: 830 kJ are required when 2.1 moles of SO3 reacts.
Answer:
M
Explanation:
I think that the measurement is m because you have to change the measurement.