Answer:
It's c.
Explanation:
Program Evaluation and Review Technique (PERT) is a method used in program management. It analyzes the time required to complete each task in a project and so tries to determine the minimum time to complete a project. It was developed by the US Navy in 1957.
In PERT analysis:
- there are 3 time estimates for every activity: optimistic, pessimistic, and most likely
-
you have to find the Critical Path. The Critical Path is the longest path of scheduled activities that must be met in order to execute a project. It is important to know because any problems on the critical path can prevent a project from moving forward and be delayed. Therefore only critical activities can contribute to the project variance.
Your answers are all Right but c d or a
Answer:
D. The outlet substitution bias injects an upward bias into the CPI
Explanation:
Answer: All of these choices are correct.
Explanation:
You didn't give the options to the question. The options include:
testing costs prior to placing the equipment into production
transportation costs
installation costs
All of these choices are correct.
Acquisition cost, is the total cost that is recognized by a company on its books for the purchase of an asset. These costs include the transportation cost, installation cost, shipping cost, testing costs, sales taxes, customs fees, etc.
Therefore, based on the explanation, the correct option is All of the choices are correct.
Answer:
≈ 9644 quantity of card
Explanation:
given data:
n = 4 regions/areas
mean demand = 2300
standard deviation = 200
cost of card (c) = $0.5
selling price (p) = $3.75
salvage value of card ( v ) = $ 0
The optimal production quantity for the card can be calculated using this formula below
= <em>u</em> + z (0.8667 ) * б
= 9200 + 1.110926 * 400
≈ 9644 quantity of card
First we have to find <em>u</em>
u = n * mean demand
= 4 * 2300 = 9200
next we find the value of Z
Z = (
)
= ( 3.75 - 0.5 ) / 3.75 = 0.8667
Z( 0.8667 ) = 1.110926 ( using excel formula : NORMSINV (0.8667 )
next we find б
б = 200
= 400