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abruzzese [7]
3 years ago
7

Alpha Particles

Physics
2 answers:
UNO [17]3 years ago
7 0

Alpha > Beta > Gamma

Explanation:

Alpha particles are the heaviest radiation whereas gamma rays are the lightest.

An alpha particle closely resembles a helium particle.

Beta particles are similar to electrons in nature

Gamma rays have no weight. They are just rays.

  Alpha particles have a mass of  4.0012amu which is that of helium

  Beta particles have a mass of 5.5 x 10⁻⁴ amu

   Gamma rays have no mass.

Learn more:

Electromagnetic radiations brainly.com/question/6818046

#learnwithBrainly

Furkat [3]3 years ago
5 0

Answer:

alpha beta gamma

Explanation:

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E_{k} = \frac{m v_{1} ^{2} }{2} -\frac{m v_{2} ^{2} }{2} +\frac{m v_{3} ^{2} }{2} \\ E_{k} = \frac{m}{2} (v_{1} ^{2}-v_{2} ^{2}+v_{3} ^{2}) \\ \\ 0.0268= \frac{0.0044}{2} (1.3 ^{2}-1.66^{2}+v_{3} ^{2}) \\ \\ 0.0536=0.0022(1.69-2.7556+v_{3} ^{2}) \\ \\ v_{3} ^{2}=25.43 \\ \\ v_{3} =+-5.04

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6. A plane due to fly from Montreal to Edmonton required refueling. Because the fuel gauge on the aircraft was not working, a me
LiRa [457]

Answer:

The amount of liters of fuel should have been added is  20093 L

Explanation:

Given that;

a mechanic used a dipstick to determine that 7682 L of fuel were left on the plane

i.e the volume of fuel left in the plane = 7682 L

Required fuel to make  a trip = 22,300 kg of fuel

Also from the question; we are being told that in order for the pilot to determine the volume ; he asked for the density of the fuel and the mechanic said 1.77.

This volume of fuel was added and the plane subsequently ran out of fuel, but landed safely by gliding into Gimli Airport near Winnipeg. The error arose because the factor 1.77 was in units of pounds per liter (lbs/L).

Now; we can understand that the density of the fuel was 1.77 pound /litre.

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1.77 pound/litre  = x kg

If we cross multiply ; we will have:

1.77 pound/litre  × 0.4536 kg = 1 pound × x kg

x kg = (1.77 pound/litre  × 0.4536 kg) /1 pound

x = 0.802872 kg/litre

\mathbf{Density = \dfrac{mass}{volume}}

where ;

mass =  22,300 kg of fuel

volume = unknown ???

density = 0.802872 kg/litre

making volume the subject of the formula from above; we have:

\mathbf{volume = \dfrac{mass}{Density}}

\mathbf{volume = 22300 \  kg \ of \ fuel *\dfrac{1 \ litre }{0.802872 \  kg \ of \ fuel}}

volume = 27775.28672 litre

volume \approx 27775 L

Let not forget that we are being told as well that the volume of fuel left in the plane = 7682 L

Now;

The amount of liters of fuel should have been added is: =  27775 L - 7682 L

The amount of liters of fuel should have been added is  20093 L

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3 years ago
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stealth61 [152]

Answer:

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