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2 years ago

Which of the following is NOT part of the general adaptation syndrome of the endocrine

1 answer:

4 0

General adaptation syndrome is made of 3 stages; alarm, resistance, and exhaustion. Reaction is NOT one of these stages.

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The design of interior spaces is relatively unimportant to good<br> architecture?

Marta_Voda [28]

The correct answer is good architecture is

7 0

3 years ago

Upper A 16-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away f

Sav [38]

Answer:

The ladder is moving at the rate of 0.65 ft/s

Explanation:

A 16-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the building at 2 feet/second. We need to find the rate at which the top of the ladder moving down when the foot of the ladder is 5 feet from the wall.

The attached figure shows whole description such that,

$x^2+y^2=256$ .........(1)

$\dfrac{dx}{dt}=2\ ft/s$

We need to find, $\dfrac{dy}{dt}$ at x = 5 ft

Differentiating equation (1) wrt t as :

$2x.\dfrac{dx}{dt}+2y.\dfrac{dy}{dt}=0$

$2x+y\dfrac{dy}{dt}=0$

$\dfrac{dy}{dt}=-\dfrac{2x}{y}$

Since, $y=\sqrt{256-x^2}$

$\dfrac{dy}{dt}=-\dfrac{2x}{\sqrt{256-x^2}}$

At x = 5 ft,

$\dfrac{dy}{dt}=-\dfrac{2\times 5}{\sqrt{256-5^2}}$

$\dfrac{dy}{dt}=0.65$

So, the ladder is moving down at the rate of 0.65 ft/s. Hence, this is the required solution.

8 0

3 years ago

Which property of sound waves decreases as the square of the distance from the source increases?

Vitek1552 [10]

Answer:

Intensity

Explanation:

The intensity of a sound wave is equal to the ratio between to the power emitted by the source divided by the area of the spherical surface through which the wave propagates:

$I=\frac{P}{4\pi r^2}$

where

P is the power

$4\pi r^2$ is the area of the spherical surface

r is the distance from the source

As we see from the formula, the intensity is inversely proportional to the square of the distance from the source:

$I\propto \frac{1}{r^2}$

so, intensity is the correct answer.

3 0

3 years ago

the maximum displacement of an oscillatory motion is A=0.49m. determine the position x at which the kinetic energy of the partic

kipiarov [429]

Answer:0.4 m

Explanation:

Given

Maximum displacement A=0.49

The sum of kinetic and elastic potential energy is $\frac{1}{2}kA^2$

where k=spring constant

U+K.E.= $\frac{1}{2}kA^2$

when K.E.=U/2

K.E.=kinetic energy

U=Elastic potential Energy

$\rightarrow \ U+\frac{U}{2}=\frac{1}{2}KA^2\\\rightarrow \ \frac{3U}{2}=\frac{1}{2}KA^2\\\rightarrow \ U=\frac{1}{3}KA^2\\\rightarrow \ \frac{Kx^2}{2}=\frac{1}{3}KA^2\\\\x=\sqrt{\frac{2}{3}}A\\x=0.4\ m$

3 0

3 years ago

Please help! Thanks so much! :)

notsponge [240]

Answer: B

Explanation: I'm not 100% sure tho sorry if i'm wrong

7 0

3 years ago