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Darina [25.2K]
3 years ago
10

Complete this equation that represents the process of nuclear fusion. Superscript 226 Subscript 88 Baseline R a yields Superscri

pt A Subscript B Baseline R n + Superscript 4 Subscript 2 Baseline H e A: B:
Physics
2 answers:
Talja [164]3 years ago
7 0

Answer:

I know that the b portion for the bottom is 86 because thats the atomic number of Rn

Explanation:

Tom [10]3 years ago
6 0

Answer:

A: 222

B: 86

Explanation:

Correct on E2020

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A 0.5 kg baseball is hit by a bat delivering an impulse of 180 kg x m/s. If the bat is in contact with the baseball for 0.4 seco
yan [13]

Answer:

450N

Explanation:

Impulse = mv    --->   180kgm/s = (0.5kg)v

v = 360 m/s

Acceleration = v/t    --->   a = (360 m/s)/(0.4s) = 900 m/s^2

Force = ma   --->   F = (0.5kg)(900 m/s^2) = 450N

Brainliest?

4 0
2 years ago
A thin film soap bubble (n=1.35) is floating in air. If the thickness of the bubble wall is 300nm, which of the following wavele
iren [92.7K]

Answer:

540 nm

Explanation:

According to the question,

The refractive index of the soap bubble, n=1.35.

The thickness of the soap bubble wall is, t=300 nm.

Now, for constructive interference of soap bubble.

2nt=(m+\frac{1}{2})\lambda.

Now for first order m=1.

Therfore,

\lambda =\frac{4}{3} tn

Substitute all the variables in the above equation.

\lambda =\frac{4}{3} (1.35)(300 nm).

Therefore,

\lambda =540 nm.

Therefore the visible light wavelength which is strongly reflected is 540 nm.

6 0
3 years ago
A 1.8 kg uniform rod with a length of 90 cm is attached at one end to a frictionless pivot. It is free to rotate about the pivot
Leokris [45]

Answer:

a. 32.67 rad/s²  b. 29.4 m/s²

Explanation:

a. The initial angular acceleration of the rod

Since torque τ = Iα = WL (since the weight of the rod W is the only force acting on the rod , so it gives it a torque, τ at distance L from the pivot )where I = rotational inertia of uniform rod about pivot = mL²/3 (moment of inertia about an axis through one end of the rod), α = initial angular acceleration, W = weight of rod = mg where m = mass of rod = 1.8 kg and g = acceleration due to gravity = 9.8 m/s² and L = length of rod = 90 cm = 0.9 m.

So, Iα = WL

mL²α/3 = mgL

dividing through by mL, we have

Lα/3 = g

multiplying both sides by 3, we have

Lα = 3g

dividing both sides by L, we have

α = 3g/L

Substituting the values of the variables, we have

α = 3g/L

= 3 × 9.8 m/s²/0.9 m

= 29.4/0.9 rad/s²

= 32.67 rad/s²

b. The initial linear acceleration of the right end of the rod?

The linear acceleration at the initial point is tangential, so a = Lα = 0.9 m × 32.67 rad/s² = 29.4 m/s²

5 0
3 years ago
A soccer player kicks a ball at rest on the
scoundrel [369]

The kinetic energy and gravitational potential energy changes during its movement from ground to the top height.

<h3>What happens to kinetic and potential energy while motion?</h3>

When the ball moves upward, its gravitational potential energy is increases and kinetic energy begins to decrease but when the ball falls towards the earth, its gravitational potential energy is transformed into kinetic energy. When the ball collides with the ground, the kinetic energy is transformed into other forms of energy.

Learn more about kinetic energy here: brainly.com/question/20658056

5 0
1 year ago
An object of volume 0.0882 m3 is
vfiekz [6]

The density of the fluid is 776.3 m^{-3}

<u>Explanation:</u>

Buoyant force is the upward pushing force whenever an object is trying to get immersed in fluid. So this is the force given by the fluid on the object which is trying to get immersed. The buoyant force is found to be directly proportional to the product of density of the object, volume of the object. And here the acceleration due to gravity will be acting as proportionality constant.

      Buoyant force = Density \times Volume \times Acceleration

As, buoyant force is given as 671 N and volume is 0.0882 m^{3} and acceleration is known as 9.8 m/s^{2}. Then density is

   \text { Density }=\frac{\text { Buoyant force }}{\text {Volume } \times \text {Acceleration}}

Thus,

   \text { Density }=\frac{671}{0.0882 \times 9.8}=\frac{671}{0.86436}=776.296 \mathrm{kg} / \mathrm{m}^{3}

Density is 776.3 kg m^{-3}.

7 0
3 years ago
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