The electric force between two charge objects is calculated through the Coulomb's law.
F = kq₁q₂/d²
The value of k is 9.0 x 10^9 Nm²/C² and the charge of proton is 1.602 x10^-19 C. Substituting the known values from the given,
2.30x10^-26 = (9.0 x 10^9 Nm²/C²)(1.602 x10^-19C)²/d²
The value of d is equal to 0.10 m.
You times the 6 by the 350 duvided 1.8
Depends in a launage or just in general the little hand is the mins and the big hand is the big numbers whole numbers time
Answer:
Gravitational potential energy (GPE) = 107.8J
Explanation:
Gravitational potential energy (GPE) = mgh
Where mass(m) = 11kg
Acceleration due to gravity(g) = 9.8m²/s
height = assumed to be 1m
Force(F) = mg
Force(F) = 11×9.8 = 107.8N
Gravitational potential energy (GPE) = 107.8×1
= 107.8J