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Kisachek [45]
3 years ago
13

A ball on a cart is moving at a rate of 2 m/s. The cart suddenly stops and the ball continues to travel in the same direction at

the same speed. This is an example of which Newton’s Laws?
Physics
2 answers:
sukhopar [10]3 years ago
7 0

Answer:

The first

Explanation:

Cause it will continue in motion till another force is applied

Nitella [24]3 years ago
3 0

Newton's law of inertia

Explanation:

I remember reading it two years ago in the science book it's not law is called Newton's law of inertia you can also look it up on Google to make sure

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Which of the following items involve a wedge? Check all that apply A. A scissors blade B. A corkscrew C. An axe D. A wheelchair
Oksanka [162]

Answer:

Axe and Scissor blade

Explanation:

6 0
4 years ago
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A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psip=75 psi. It had a wall thickness
Mekhanik [1.2K]

To solve this problem we must apply the concept related to the longitudinal effort and the effort of the hoop. The effort of the hoop is given as

\sigma_h = \frac{Pd}{2t}

Here,

P = Pressure

d = Diameter

t = Thickness

At the same time the longitudinal stress is given as,

\sigma_l = \frac{Pd}{4t}

The letters have the same meaning as before.

Then he hoop stress would be,

\sigma_h = \frac{Pd}{2t}

\sigma_h = \frac{75 \times 8}{2\times 0.25}

\sigma_h = 1200psi

And the longitudinal stress would be

\sigma_l = \frac{Pd}{4t}

\sigma_l = \frac{75\times 8}{4\times 0.25}

\sigma_l = 600Psi

The Mohr's circle is attached in a image to find the maximum shear stress, which is given as

\tau_{max} = \frac{\sigma_h}{2}

\tau_{max} = \frac{1200}{2}

\tau_{max} = 600Psi

Therefore the maximum shear stress in the pressure vessel when it is subjected to this pressure is 600Psi

6 0
3 years ago
PLEASE HELP ME
vichka [17]
Go with the last one because you need potential energy for kinetic energy
8 0
3 years ago
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A swan on a lake gets airborne by flapping its wings and running on top of the water. If the swan must reach a velocity of 6.00
ira [324]

Answer:

A. 51.42 m.

B. 17.14 s.

Explanation:

Using equations of motion:

vf^2 = vi^2 + 2 * aS

Where,

vf = final velocity

a = acceleration

S = distance to which swan traveled

vi = 0 m/s

6.00^2 = 2 * 0.350S

S = 36/0.7

= 51.42 m.

B.

vf = vi + at

6 = 0 + 0.35t

t = 6/0.35

= 17.14 s.

5 0
3 years ago
Will mark brainliest
son4ous [18]

Answer:

One 200 is bigger than 100

Explanation:

6 0
3 years ago
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