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Kisachek [45]
3 years ago
13

A ball on a cart is moving at a rate of 2 m/s. The cart suddenly stops and the ball continues to travel in the same direction at

the same speed. This is an example of which Newton’s Laws?
Physics
2 answers:
sukhopar [10]3 years ago
7 0

Answer:

The first

Explanation:

Cause it will continue in motion till another force is applied

Nitella [24]3 years ago
3 0

Newton's law of inertia

Explanation:

I remember reading it two years ago in the science book it's not law is called Newton's law of inertia you can also look it up on Google to make sure

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PLEASE HELP!!!!! which statements correctly conpare the masses of protons,neutrons,and electrons​
Anastasy [175]
Protons and neutrons have similar mass
Electrons are smaller then a proton or a neutron
8 0
3 years ago
A tow truck drags a stalled car along a road. The chain makes an angle of 30° with the road and the tension in the chain is 1400
AURORKA [14]

Answer:

The work is done by the truck pulling the car 1 km is 1,212,436 J

Explanation:

Work is defined as the force that is applied on a body to move it from one point to another. When a force is applied, an energy transfer occurs. Then it can be said that work is energy in motion.

So work is one of the forms of energy transmission between bodies. To perform a job, you must exert a force on a body and it moves.

In the International System of Units, work is measured in Joule. A Joule is the work that a constant force of 1 Newton does on a body that moves 1 meter in the same direction and direction as the force. Then, Joule is equivalent to Newton per meter.

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves:

Work= Force*Distante* cos (θ)

In this case:

  • Force= 1,400 N= 1,400 kg*\frac{m}{s^{2} }
  • Distance= 1 km= 1,000 m
  • θ= Angle that exists between the direction of the force and the direction= 30°

Replacing:

Work= 1,400 N* 1,000 m* cos (30°)

Work= 1,212,435. 565 Joule≅ 1,212,436 J

<u><em> The work is done by the truck pulling the car 1 km is 1,212,436 J</em></u>

7 0
3 years ago
A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the magnitude of the dri
nordsb [41]

Complete Question

A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm2.) mm/s

Answer:

The drift velocity is v  = 0.0002808 \ m/s

Explanation:

From the question we are told that

    The current on the copper is  I  = 20 \ A

     The cross-sectional area is  A =  5.261 \ mm^2 =  5.261 *10^{-6} \ m^2

The number of copper atom in the wire is  mathematically evaluated

      n  =  \frac{\rho *  N_a}Z}

Where \rho is the density of copper with a value \rho =  8.93 \ g/m^3

          N_a is the Avogadro's number with a value N_a  = 6.02 *10^{23}\ atom/mol

         Z  is the molar mass of copper with a value  Z =  63.55 \ g/mol

So

     n  =  \frac{8.93 * 6.02 *10^{23}}{63.55}

     n  = 8.46 * 10^{28}  \  atoms /m^3

Given the 1 atom is equivalent to 1 free electron then the number of free electron is  

         N  = 8.46 * 10^{28}  \  electrons

The current through the wire is mathematically represented as

         I  =  N * e * v * A

substituting values

        20 =  8.46 *10^{28} * (1.60*10^{-19}) * v *  5.261 *10^{-6}

=>     v  = 0.0002808 \ m/s

       

8 0
3 years ago
Ten point on important of sports and games in human life​
pishuonlain [190]
They make your muscles stronger and keep the bones, heart, and lungs in good condition. It implies that you have less chance of blood clotting and heart attack. one can balance his mood well and is likely to experience less stress in life.It also helps us to practice discipline.
6 0
3 years ago
A -1.12 μC charge is placed at the center of a conducting spherical shell, and a total charge of +8.65 μC is placed on the shell
Lisa [10]

Answer: 7.53 μC

Explanation: In order to explain this problem  we have to use the gaussian law so we have:

∫E.dS=Qinside/εo we consider a gaussian surface inside the conducting spherical shell so E=0

Q inside= 0 = q+ Qinner surface=0

Q inner surface= 1.12μC so in the outer surface the charge is (8.65-1.12)μC=7.53μC

7 0
4 years ago
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