Question

Solve each system using the elimination method 4x-y=-2 2x+y=2

Answer 1

Answer:

$\left \{ {{x=0} \atop {y=2}} \right.$

Step-by-step explanation: $\left \{ {{4x-y=-2} \atop {2x+y=2}} \right.$

Add the two equations

$4x-y+(2x+y)=-2+2$

Remove parentheses

$4x-y+2x+y=-2+2$

Cancel one variable

$4x+2x=-2+2$

Apply the Inverse Property of Addition

$4x+2x=0$

Combine like terms

$6x=0$

Divide both sides by the equation by the coefficient of variable

$x=0$

Substitute into one of the equations

$2\times0+y=2$

Apply Zero Property of Multiplication

$y=2$

The solution of the system is

$\left \{ {{x=0} \atop {y=2}} \right.$

I hope this helps you

:)