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FromTheMoon [43]
3 years ago
7

A student using this technique finds that when putting a hot piece of metal into a calorimeter which contains 35.070g of water,

the water temperature increases from 22.4 c to 24.7
c. how much heat (q) was absorbed by the water (s.h of water = 4.184 j/g k)
Chemistry
1 answer:
Aleks04 [339]3 years ago
5 0
Q=cmΔt,

c=<span>4.184 j/(g*⁰C)
m=35.070 g
</span>Δt=t(final)-t(initial) = 24.7-22.4=2.3⁰C
<span>
Q=4.184</span> j/(g*⁰C)* 35.070 g * 2.3⁰C ≈ 337.49 J ≈ 338 J
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4 0
4 years ago
A species with a charge of -1 contains 57 electrons and 80 neutrons. What is the identity of the species. Note: The species show
Inga [223]

In a neutral atom, the number of protons is equal to the number of electrons.

Given that the charge on the ion of the element is -1. This means that there is one electron more than the number of protons in the element.

The atomic number = Number of protons = 57 -1 = 56

Element with atomic number 56 is Barium.

Mass number of the element = Number of protons + Number of neutrons

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3 years ago
A sample of ammonia is found to occupy 0.250 L under laboratory conditions of 27 °C and 0.850 atm. Find the volume of this sampl
Rzqust [24]

Answer:

0.193 L

Explanation:

Step 1:

Data obtained from the question.

Initial Volume (V1) = 0.250 L

Initial temperature (T1) = 27°C

Initial pressure (P1) = 0.850 atm

Final volume (V2) =?

Final temperature (T2) = 0°C

Final pressure (P2) = 1.00 atm

Step 2:

Conversion of celsius temperature to Kelvin temperature.

Temperature (Kelvin) = temperature (celsius) + 273

Initial temperature (T1) = 27°C = 27°C + 273 = 300K

Final temperature (T2) = 0°C = 0°C + 273 = 273K

Step 3:

Determination of the new volume of the sample of ammonia gas.

The new volume can be obtain by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

0.850x0.250/300 = 1xV2/273

Cross multiply to express in linear form

300 x V2 = 0.850x0.250x273

Divide both side by 300

V2 = (0.850x0.250x273) /300

V2 = 0.193 L

Therefore, the volume of the sample at 0 °C and 1.00 atm is 0.193 L

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3 years ago
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When 1-bromo propane is reacted with sodium metal, the propane and sodium bromide are formed.

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Learn more about 1-bromo propane here: brainly.com/question/25597694

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