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FromTheMoon [43]
3 years ago
7

A student using this technique finds that when putting a hot piece of metal into a calorimeter which contains 35.070g of water,

the water temperature increases from 22.4 c to 24.7
c. how much heat (q) was absorbed by the water (s.h of water = 4.184 j/g k)
Chemistry
1 answer:
Aleks04 [339]3 years ago
5 0
Q=cmΔt,

c=<span>4.184 j/(g*⁰C)
m=35.070 g
</span>Δt=t(final)-t(initial) = 24.7-22.4=2.3⁰C
<span>
Q=4.184</span> j/(g*⁰C)* 35.070 g * 2.3⁰C ≈ 337.49 J ≈ 338 J
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How many moles is in 2.52*10^24 molecules of water?
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Hi friend
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Your answer
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Water = H2O

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Given number of molecules = 2.52 × 10²³

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Number of moles =
\frac{2.52 \times 10 {}^{24} }{6.022 \times 10 {}^{23} }  \\  \\  = 4.184 \: (approximately)

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Read 2 more answers
Potassium-40 can decay into either calcium-40 or argon-40. All three of these atoms have essentially the same weight. Ninety per
hram777 [196]
Answser:

3.77 mg of K-40 decayed into Ar-40.

Data:

1) K-40, Ca-40, Ar-40: all three have the same atomic mass
2) 90%<span> of the potassium-40 will decay into calcium-40
3) 10% of the potassium-40 will decay into argon-40.</span>
4) K-40 inside the rock = 0.81 mg
5) Ar-40 trapped = 0.377 mg

Soltuion:

1) 0.377 mg of Ar-40 is the 10% of the mass of the K-40 that decayed

=> x * 10% = 0.377 mg => x * 0.1 = 0.377mg

=> x = 0.377 mg / 0.1 = 3.77 mg

That means that 3.77 mg of K-40 decayed into Ar-40. And this is the answer to the question.

Additionaly, you can analyze the content of all K-40 and Ca-40, to understand better the case.

2) The mass of the K-40 that decayed into Ca-40 is 9 times (ratio 9:1) the amount that decayed into Ar-40 =>

mass of K-40 that decayed into Ca-40 = 9 * 0.377 = 3.393 mg

3) Total amount of K-40 that decayed = amount that decayed into Ar-40 + amount that decayed into Ca-40 = 0.377mg + 3.393mg = 3.77 mg

4) Original amount of K-40 = amount of K-40 that decayed + amount of K-40 present in the rock = 3.77mg + 0.81 mg = 4.58 mg

5) amount of K-40 that decayed into Ar-40 as percent

% = [3.77 mg / 4.58mg] * 100 = 82.31 %.



4 0
3 years ago
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