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2 years ago

How are owls compared to wolfs?

Chemistry

2 answers:

xenn [34]2 years ago

6 0

Answer:

They are both very aggressive animals! And amazing hunters at night!

Explanation:

I hope this helps! :)

garik1379 [7]2 years ago

4 0

Answer:

Owl and wolfs dodnt really have simuarities tbh lol, but they are both fercious animals :)

Explanation:

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HHHHHEEEELLLLLPPP PPPLLEEASEEE I GIVE BRAINLIEST!!!!!!!!!

svet-max [94.6K]

1. a. FeS + 2HCl --> FeCl2 + H2S
b. This is a double- replacement reaction. (The elements "switch partners".)

2. a.2Na + F2 --> 2NaF
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4. Hydrogen gas reacts with oxygen gas to create water in a composition/synthesis reaction.

I hope these answers will help you! If you need any explanation, ask and hopefully I can get back to you. ;)

8 0

3 years ago

The value of Henry's law constant for oxygen in water at 242C is 1.66 x 1 ox M/torr. b. c. Calculate the solubility of oxygen in

DochEvi [55]

25ca an the oxygen gas is 2 atom ur mum

4 0

3 years ago

Which of the following pairs of elements belong to the same group

ale4655 [162]

C. C and Pb; Carbon and Lead being in the same group.

5 0

3 years ago

A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp

vichka [17]

Answer:

The balanced chemical equation:

$C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)$

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

$C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)$

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = $T_1= 21.36^oC$

Final temperature of the calorimeter = $T_2= 26.37^oC$

Heat absorbed by calorimeter = Q

$Q=C\times \Delta T$

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

$\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g$

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

$\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol$

3 0

3 years ago

Volume and moles are __________ related. This relationship can be calculated by using ___________ Law.

Kryger [21]

Answer:

The correct answer is - directly; Avogadro’s.

Explanation:

At the same temperature and pressure, gases of the same or equal volume have the same number of molecules. The relation between the moles of the gases and the volume of the gases are indirectly proportional to one another at the same temperature and pressure. This law is called Avogadro's law. In the case of an ideal gas of a particular mass has the volume and moles are directly proportional.

Thus, the correct answer is - directly; Avogadro’s.

6 0

3 years ago