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Yuri [45]
2 years ago
13

Solve the system of equations. y=x-1 y=-x-5

Mathematics
2 answers:
koban [17]2 years ago
8 0

There is something wrong with the question. Check it again

lyudmila [28]2 years ago
7 0

Answer:

there is some mistake in question

Step-by-step explanation:

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Write the sentence as an inequality.
kramer

Answer:

N < 6 or   N \leq -7 or N > 12

Hope this helps. <em>lmk</em>.

6 0
3 years ago
Why did my DAD leave me is it because he needed to get some milk or to get some more pop from the store? Why would I know Im jus
mart [117]

Answer:

I have 1 question, and 1 question only, WHO t.f says "pOp" like nooooo its "SODA"

and your dad sucks for leaving but im sure he has a good reason

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
6 times what would = 73
padilas [110]

Answer:

12.1 repeating

Step-by-step explanation:

73/6=12.16666666...

6 0
3 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
Part A
SpyIntel [72]

Answer:

110 + 10x ; 40x

4

Step-by-step explanation:

Given that:

For every visit to Arts museum:

Scenario 1:

Parking fee = $15

Admission fee = $25

Total amount for scenario 1:

If number of visits = x

Total cost = $(15 + 25) × number of visits

Total cost : $40x

With membership :

Price of membership = $110 (one time payment)

Parking fee = $10

Admission fee = $0

Let number of visits = x

Total cost :

Membership fee + (parking fee × number of visits)

$110 + ($10 * x)

= 110 + 10x

B) number of visits for which member cost is less than non-member cost :

Member cost = 110 + 10x

Non member cost = 40x

110 + 10x < 40x

10x - 40x < 110

-30x < 110

x > 3.67

Hence x = 4

Number of visits for which member cost is greater than non member cost is 4

4 0
3 years ago
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