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ss7ja [257]
2 years ago
13

Which characteristic is given by the angular momentum quantum number?

Chemistry
1 answer:
chubhunter [2.5K]2 years ago
3 0

Answer:

orbital shape.

Explanation:

1) There are four quantum numbers to describe the electrons. These are:

i) Principal quantum number (n)

ii) Azimuthal quantum number (ℓ), also called angular momentum quantum number.

iii) Magnetic quantum number (m)

iv) Spin quantum number (s)

2) The principal quantum number tells the main energy level. It can be 1, 2, 3, 4, 5, 6, 7. It is related to the orbital size. 1 is a small orbital, 7 is a big orbital.

2) The Azimuthal quantum number (ℓ) or angular momentum quantum number may be a number between 0 and n - 1.

It tells the kind of orbital, which is its shape

The correspondence is:

0 = s orbital,

1 = p orbital,

2 = d orbital,

3 = f orbital.

3) Magnetic quantum number (m) tells the orientation. It can be from - ℓ to + ℓ

For example when ℓ = 1, the orbital is p, and the magnetic quantum number may be -1, 0, or +1, which corresponds to px, py, pz: the orientation of the p orbital in the space.

4) Spin quantum number (s) can be either +1/2 or -1/2.

JM~ Hope this helps you out

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A 3.452 g sample containing an unknown amount of a Ce(IV) salt is dissolved in 250.0-mL of 1 M H2SO4. A 25.00 mL aliquot is anal
SOVA2 [1]

Answer:

1,812 wt%

Explanation:

The reactions for this titration are:

2Ce⁴⁺ + 3I⁻ → 2Ce³⁺ + I₃⁻

I₃⁻ + 2S₂O₃⁻ → 3I⁻ + S₄O₆²⁻

The moles in the end point of S₂O₃⁻ are:

0,01302L×0,03428M Na₂S₂O₃ = 4,463x10⁻⁴ moles of S₂O₃⁻. As 2 moles of S₂O₃⁻ react with 1 mole of I₃⁻, the moles of I₃⁻ are:

4,463x10⁻⁴ moles of S₂O₃⁻×\frac{1molI_{3}^-}{2molS_{2}O_{3}^-} = 2,2315x10⁻⁴ moles of I₃⁻

As 2 moles of Ce⁴⁺ produce 1 mole of I₃⁻, the moles of Ce⁴⁺ are:

2,2315x10⁻⁴ moles of I₃⁻×\frac{2molCe^{4+}}{1molI_{3}^-} = 4,463x10⁻⁴ moles of Ce(IV). These moles are:

4,463x10⁻⁴ moles of Ce(IV)×\frac{140,116g}{1mol} = <em>0,0625 g of Ce(IV)</em>

As the sample has a 3,452g, the weight percent is:

0,0625g of Ce(IV) / 3,452g × 100 = <em>1,812 wt%</em>

I hope it helps!

5 0
3 years ago
Digoxin is available in a concentration of 0.1 mg/ml. How many ml are required to administer a 75 mcg dose?
Step2247 [10]

Answer : The volume required to administer a 75 mcg dose are, 0.75 mL

Explanation : Given,

Concentration of Digoxin = 0.1 mg/mL

That means, 0.1 mg of Digoxin present in 1 mL of solution.

Mass of dose = 75 mcg = 0.075 mg

Conversion used : (1 mcg = 0.001 mg)

Now we have to determine the volume required to administer a 75 mcg dose.

As, 0.1 mg of Digoxin required in 1 mL of solution

So, 0.075 mg of Digoxin required in \frac{0.075mg}{0.1mg}\times 1mL=0.75mL of solution

Thus, the volume required to administer a 75 mcg dose are, 0.75 mL

5 0
3 years ago
True or false : Color Changes are used to show reaction completion
Aleks [24]

Answer:

True

Explanation:

It means the reaction is occuring.

7 0
3 years ago
Acetylene gas (C2H2) is used in welding torches. When it reacts with oxygen, it produces
Vikki [24]

Mass C₂H₂ needed : 22.165 g

<h3>Further explanation</h3>

Reaction

2C₂H₂+ 5O₂ ⇒ 4CO₂ + 2H₂O

75.0 grams of CO₂ , mol CO₂ (MW=44 g/mol) :

\tt \dfrac{75}{44}=1.705

mol C₂H₂ :

\tt \dfrac{2}{4}\times 1.705=0.8525

mass C₂H₂ (MW=26 g/mol) :

\tt 0.8525\times 26=22.165~g

8 0
3 years ago
Identify the reasons that cities boomed during the Middle Ages.
atroni [7]

Answer:

Explanation:

The reasons that cities boomed during the Middle Ages are more employment opportunities, increased trade, and growing interest in culture and art.

7 0
3 years ago
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