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Blababa [14]
2 years ago
14

Why can't we separate azeotropes with the distillation process?.

Chemistry
1 answer:
liraira [26]2 years ago
6 0

Answer:

have just recently learnt the theory of fractional and normal distillations and the basics of maximum and minimum boiling azeotropes.

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Is it true that Organisms need water, vitamins and minerals. But they do not need salt to function.
Veseljchak [2.6K]
All organisms need water, vitamins, minerals, and salt together to balance things out.
5 0
3 years ago
For each of the following circumstances, indicate whether the calculated molarity of NaOH would be lower, higher or unaffected.
irina [24]

Answer:

a)calculated molarity of NaOH would be lower

b) calculated molarity of NaOH would be lower

c) calculated molarity of NaOH would be lower

d) calculated molarity of NaOH would be unaffected

Explanation:

Let us recall that the reaction of NaOH and HCl is as follows;

NaOH(aq) + HCl(aq) ----> NaCl(aq) + H2O(l)

Since the reaction is 1:1, when the number of moles of HCl reacting with NaOH is low due to dilution, the calculated molarity of NaOH also becomes less than it's accurate value.

When 40mL of water is added to the titration flask rather than 25ml of water, the acid is more dilute hence less number of moles of acid than necessary reacts with the base thereby yielding a less than accurate value of the molarity of NaOH.

If the burette wet with water is not rinsed with NaOH solution, the concentration of the NaOH in the burette decreases due to dilution with water and a less than accuracy value is calculated for the molarity of NaOH.

If five drops of phenolphthalein is used instead of one or two drops, there is no qualms since enough phenolphthalein may be added to ensure that a sharp end point is obtained.

8 0
3 years ago
Why is 15 m acetic acid an appropriate solvent in which to perform rate studies of electrophilic bromintations?.
Alekssandra [29.7K]

Acetic acid activates the bromine and makes it a better electrophile.

<h3>What is bromination?</h3>

When a substance undergoes bromination, bromine is added to the compound as a result of the chemical reaction. After bromination, the result will have different properties from the initial reactant.

<h3>Why is 15M acetic acid used as a solvent for bromination?</h3>

DCM (dichloromethane) requires more time. Acetic acid has protons that can give one of the Br (bromine) a positive charge and activate it. There is a brief loss of aromaticity that calls for high energy activation.

Refer to the attached image for bromination reaction.

Learn more about bromination here:

brainly.com/question/26428023

#SPJ4

Download docx
8 0
10 months ago
Read 2 more answers
The chemical equation for a reaction between K2Cr2O7 and HCl is shown. K2Cr2O7 + 14HCl → 2CrCl3 + 2KCl + 3Cl2 + 7H2O
guapka [62]

<u>Answer: </u>The correct answer is Option b.

<u>Explanation:</u>

Oxidizing agent is defined as the chemical reagent which helps the other chemical compound to get oxidized and itself gets reduced. The oxidation state for these species gets reduced because they are undergoing reduction reaction.

For the given chemical equation:

K_2Cr_2O_7+14HCl\rightarrow 2CrCl_3+2KCl+3Cl_2+7H_2O

Oxidation state of Chromium is getting reduced from +6 to +3 and oxidation state of chlorine getting increased from -1 to 0.

Hence, K_2Cr_2O_7 acts like and oxidizing agent because it is itself getting reduced to CrCl_3

Therefore, the correct answer is Option b.

4 0
3 years ago
A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO
Akimi4 [234]

Answer: The empirical formula for the given compound is CH_2

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=22.0g

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, \frac{12}{44}\times 22.0=6g of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = \frac{0.5}{0.5}=1

For Hydrogen  = \frac{1.0}{0.5}=2

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is C_{1}H_{2}=CH_2

4 0
3 years ago
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