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iren2701 [21]
3 years ago
8

The question is below

Chemistry
1 answer:
Nezavi [6.7K]3 years ago
3 0
The correct conditions for measuring reduction potentials (the tendency to acquire electrons and become reduced), is 25C and 1M (or 1 mole/litre) for reactants - ANSWER B.
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41 to
tia_tia [17]

Answer:

d = 0.9 g/L

Explanation:

Given data:

Number of moles = 1 mol

Volume = 24.2 L

Temperature = 298 K

Pressure = 101.3 Kpa (101.3/101 = 1 atm)

Density of sample = ?

Solution:

PV = nRT     (1)

n = number of moles

number of moles = mass/molar mass

n = m/M

Now we will put the n= m/M in equation 1.

PV = m/M RT   (2)

d = m/v

PM = m/v RT ( by rearranging the equation 2)

PM = dRT

d = PM/RT

The molar mass of neon is = 20.1798 g/mol

d = 1 atm × 20.1798 g/mol / 0.0821 atm. L/mol.K × 273K

d = 20.1798 g/22.413 L

d = 0.9 g/L

4 0
3 years ago
Jenny places a strip of pH paper into a solution. When she removes the pH paper, it has turned yellow-green.
Ronch [10]
Jenny puts the ph paper and lines it up PH SCALE to find how strong the solution.
4 0
3 years ago
Read 2 more answers
Which explains how burning a magnesium ribbon highlights a toolmark?
Setler [38]
<h2>Answer:</h2>

The magnesium ribbon, <u>D. It forms a material to cast the tool mark</u>.

<h2>Explanation:</h2>

When a magnesium ribbon is burnt in the presence of oxygen it gives out strong light and heat is produced. Apart from it, it leads to the production of substance called as magnesium oxide which is formed as the product due to the reaction of magnesium with the oxygen present in the air.

Tool marks are the mark which is created by tools while using them. In order to identify or locate them castes made up of magnesium oxide is utilized. When this is pasted on the suspected area, the tool mark of the suspected tool gets pasted on it.

6 0
4 years ago
How many times greater is one gallon than one quart
horrorfan [7]
4, because there are 4 quarts in 1 gallon. 

Another way to think about it is 1 gallon= $1 and 1 quart= 25 cents 
There are 4 quarters in a dollar.

Hope this helped..
8 0
3 years ago
A certain man needed 400N of force to pull a load through a distance of 150cm in 8s . Calculatell i) the work done by man ii) th
Igoryamba

Answer:

a) 600 J

b) 75 W

Explanation:

Force= 400 N, distance = 150 cm = 1.5 m, time= 8s

a) Work is the product of force acting on an object and distance (or displacement). The S.I unit of work is the joules.

Work = force × distance = 400 × 1.5 = 600 J

b) Power is the amount of energy transferred per unit time. It is the ratio of work to time. The S.I unit of power is watt

Power = work/time = 600 / 8 = 75 W

5 0
3 years ago
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