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solmaris [256]
4 years ago
15

1. Starting with 9.3 moles of O 2 , how many moles of H 2 S will be needed and how many moles of SO 2 will

Chemistry
1 answer:
enyata [817]4 years ago
6 0

Answer:

Moles of H₂S needed = 6.2 mol

Moles of SO₂ produced = 6.2 mol

Explanation:

Given data:

Number of moles of O₂ = 9.3 mol

Moles of H₂S needed = ?

Moles of SO₂ produced = ?

Solution:

Chemical equation:

2H₂S + 3O₂      →    2SO₂ + 2H₂O

Now we will compare the moles of oxygen with H₂S.

                  O₂             :           H₂S

                    3             :             2

                   9.3            :         2/3×9.3 = 6.2 mol

Now we will compare the moles of SO₂ with both reactant.

                   O₂             :            SO₂

                    3              :               2

                   9.3            :         2/3×9.3 = 6.2 mol      

                 H₂S             :            SO₂

                    2              :               2

                   6.2            :          6.2 mol      

So 6.2 moles of  SO₂ are produced.

         

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If the pellets represent particles in matter, what do you think the shaking represents?
hammer [34]

Answer:

This question is incomplete. The completed question is below

Procedure

1. Read and complete a lab safety form.

2. Place about 50 copper pellets into  a plastic petri dish. Place the cover  on the dish, and secure it with tape.

3. Hold the dish by the edges. Gently  vibrate the dish from side to side no  more than 1–2 mm. Observe the  pellets. Record your observations in  your Science Journal.

4. Repeat step 3, vibrating the dish less  than 1 cm from side to side.

5. Repeat step 3, vibrating the dish  3–4 cm from side to side.

if the pellets represent particles in matter, what do you think the shaking represents?

Explanation:

This procedure seeks to illustrate the "properties" of particles in matter. The shaking of the pellets represents the movement of the particles of matter (which occurs in liquids and gases). This is because the movement of particles in a liquid and gaseous state freely moves around (reason the petri-dish was vibrated so the pellet particles which serve as the liquid/gaseous particles can move freely).

NOTE: The particles in a solid have a highly restricted movement (or no movement) because of the compact nature of the particles within the solid.

3 0
3 years ago
A three-step process for producing molten iron metal from Fe2O3 is: 3Fe2O3 + CO → 2Fe3O4 + CO2 Fe3O4 + CO → 3FeO + CO2 FeO + CO
miskamm [114]

Answer:

There is 100.4652 kg of iron produced from 390 kg of Fe2O3

Explanation:

<u>Step 1</u>: Given data

3Fe2O3 + CO → 2Fe3O4 + CO2

Fe3O4 + CO → 3FeO + CO2

FeO + CO → Fe + CO2

Mass of Fe2O3 = 390 kg = 390000 grams

Molar mass of Fe2O3 = 159.69 g/moles

<u>Step 2: </u>Calculate moles of Fe2O3

Moles of Fe2O3 = mass of Fe2O3 / Molar mass of Fe2O3

Moles of Fe2O3 = 390000 grams / 159.69 g/moles = 2442.2 moles

<u>Step 3</u>: Calculate expected moles of Fe3O4

In the first equation, for 3 moles of Fe2O3 consumed ,we get 2 moles of Fe3O4. The mole ratio is 3:2

This means if we consume 2442.2 moles of Fe2O3, there will be produced 2/3 * 2442.2 = 1628.2 moles of Fe3O4

Since the yield for the step is only 84.6 %

This will be 0.846 * 1628.2 = 1377.4 moles of Fe3O4

<u>Step 4:</u> Calculate expected moles of FeO

In the second equation, for 1 mole of Fe3O4 consumed, there is produced 3 moles of FeO

This means for 1377.4 moles of Fe3O4 consumed, there is 3*1377.4 = 4132.2 moles of FeO produced

Since the yield for the step is only 50.8%

This will be 0.508 * 4132.2 = 2099.2 moles of FeO

<u>Step 5:</u> Calculate expected moles of Fe

In the third equation, for 1 mole of FeO consumed, there is produced 1 mole of Fe.

This means for 2099.2 moles of FeO consumed, there is also 2099.2 moles of Fe produced

Since the yield is only 85.7%

This will be 0.857 * 2099.2 = 1799 moles of Fe

<u>Step 6:</u> Calculate mass of Fe

Mass of Fe = moles of Fe * Molar mass of Fe

Mass of Fe = 1799 moles of Fe * 55.845 g/moles = 100465.2 grams = 100.4652 kg of Fe

There is 100.4652 kg of iron produced from 390 kg of Fe2O3

6 0
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25% is the answer to the question
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Answer:

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Answer:

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8 0
3 years ago
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