All categories

2 years ago

State at least 2 uses for pinhole cameras

2 answers:

6 0

The image formed by a pinhole camera may be projected onto a translucent screen for a real-time viewing or safe observation of the solar eclipse.
A common use of pinhole photography is to capture the movement of the sun.

____ [38]2 years ago

4 0

Explanation:

A common use of pinhole photography is to capture the movement of the sun over a long period of time. This type of photography is called solargraphy. Pinhole photography is used for artistic reasons, but also for educational purposes to let pupils learn about, and experiment with, the basics of photography.

i guess

You might be interested in

What is a

lawyer [7]

Answer:

A. They are a solid.

Explanation:

Hope this helps. . .

uwu

3 0

3 years ago

Read 2 more answers

A book has a mass of 50 grams and an acceleration of 5 m/s/s. What is the force on the book?

Ivan

Answer:

250 newtons i belive.

Explanation:

8 0

3 years ago

When distances were carefully measured from the Earth to globular clusters above and below the Milky Way plane (where our view o

uranmaximum [27]

Answer:

A) Spherically symmetric about a point in the constellation Sagittarius and concentrated in that direction

Explanation:

The globular clusters are present mainly in the direction of Sagittarius with the center of the system of globular cluster being measured as a spherical cluster cloud such that the center of the Milky Way can be taken as being in the Sagittarius constellation

4 0

3 years ago

An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the

olga2289 [7]

Answer:

vi = 14.610

Explanation:

initial velocity of the first object (vi) = 0 m/s, because it was dropped

distance (y) = -20 m

initial position (y0) = 0 m

acceleration due to gravity (g) = -9.8 m/s^2

y = 1/2 gt^2 + vi*t + y0

-20 = 1/2(-9.8)t^2 + 0 + 0

-20 = -4.9t^2

4.081 = t^2

+√4.081 = t

t = 2.020

time of second object = 2.020 - 1 = 1.020

Now we can plug in the new time to solve for vi of the second object.

y = 1/2 gt^2 + vi*t + y0

-20 = 1/2(-9.8)1.020^2 + vi*1.020 + 0

-20 = -5.098 + 1.020vi

14.902 = 1.020vi

vi = 14.610 m/s

6 0

3 years ago

A 5-N force is applied to a 3-kg ball to change its velocity from 9 m/s to 3 m/s. The impulse is encountered by the ball for a t

anyanavicka [17]

Answer:

3.6 s.

Explanation:

Impulse: This can be defined as the product of force and time. The S.I unit of impulse is N.s.

From newton's second law of motion,

The expression for impulse is given as,

I = Ft = m(u-v) ................. Equation 1

make t the subject of the equation

t = m(v-u)/F................... Equation 2

Where I = impulse, v = final velocity, u = initial velocity, m = mass of the ball, F = force, t = time

Given: m = 3 kg, F = 5 N, u = 9 m/s, v = 3 m/s

Substitute into equation 2

t = 3(9-3)/5

t = 3(6)/5

t = 3.6 s.

4 0

4 years ago