Question

A 5-N force is applied to a 3-kg ball to change its velocity from 9 m/s to 3 m/s. The impulse is encountered by the ball for a time of ____ seconds.

Answer 1

Answer:

3.6 s.

Explanation:

Impulse: This can be defined as the product of force and time. The S.I unit of impulse is N.s.

From newton's second law of motion,

The expression for impulse is given as,

I = Ft = m(u-v) ................. Equation 1

make t the subject of the equation

t = m(v-u)/F................... Equation 2

Where I = impulse, v = final velocity, u = initial velocity, m = mass of the ball, F = force, t = time

Given: m = 3 kg, F = 5 N, u = 9 m/s, v = 3 m/s

Substitute into equation 2

t = 3(9-3)/5

t = 3(6)/5

t = 3.6 s.