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Sindrei [870]
3 years ago
12

Each week Samantha , can pay as much as $15 , for her school lunch. Write an inequality showing how much Samantha spend on lunch

?

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
3 0
To represent all the possible amounts that Samantha can pay, you will write that x is less than or equal to 15.

This means that any amount up to and including 15 is a possibility.

See the attached picture for the inequality.

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Which of the following statements is true about completing a square? A. When completing the square, subtract the square of half
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Answer:

D

Step-by-step explanation:

So, let's say that we have the following equation:

x^2+bx=0

And we want to complete the square.

What we need to do is to divide the coefficient of x by half. Square that. Then add that number to both sides.

The answer that reflects this is choice D.

For instance if we have:

x^2+4x=0

Divide 4 by 2 and then square it.

4/2 is 2. 2²=4. Add 4 to both sides. Thus:  

(x^2+4x)+4=0+4

And now, we can complete the square:

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5 0
3 years ago
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Which problem situation corresponds to<br> the equation 2.85 = 1.35 + 0.75x?
Ksju [112]
The answer is A !!!!!

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5 0
2 years ago
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jonny [76]
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7 0
3 years ago
Which statement is true about the polynomial after it has been simplified. -10m^4n^3+8m^2n^6-6m^2n^6
laila [671]

Answer: 2m^2n^3 x ( -5m^2 + 4n^2 -3n^2 )

Step-by-step explanation:

<em>ok</em><em>,</em><em> so just let me</em><em>,</em><em> uh</em><em>,</em><em> make this a little easier on my eyes lol:</em>

-10m^4n^3+8m^2n^6-6m^2n^6 ----> (-10m^4)(n^3) + (8m^2)(n^6) - (6m^2)(n^6)

<em>I just put in parentheses. nothing changed. just parentheses. </em>

Since the leading coefficients, -10 , 8 , and 6 are multiples of two,

we can take out 2 from each... [-10/2 = 5 , 8/2 = 4 , 6/2 = 3 ]

= 2 x [ (-5m^4)(n^3) + (4m^2)(n^6) - (3m^2)(n^6) ]

Looking at it now...

<em>we can take out m^2 from each... </em>m^4 , m^2 , and m^2

m^2 [m^2 , 1 , 1]

since    m^4 /m^2 = m^2 , m^2 /m^2 = 1 , m^2 /m^2 = 1

= 2(m^2) x [ (-5m^2)(n^3) + (4x1)(n^6) - (3x1)(n^6) ]

= 2(m^2) x [ (-5m^2)(n^3) + (4)(n^6) - (3)(n^6) ]

Finally, one more step...

<em>we can take out n^3 from each term.... </em>n^3 , n^6 , and n^6

n^3 [1 , n^2 , n^2] since n^3 /n^3 = 1 , n^6 /n^3 = n^2 , n^6 /n^3 = n^2

= 2(m^2)(n^3) [ (-5m^2)(1) + (4)(n^2) - (3)(n^2) ]

= 2m^2n^3 x [ (-5m^2) + (4n^2) - (3n^2) ]

= 2m^2n^3 x ( -5m^2 + 4n^2 -3n^2 )

ANSWER: 2m^2n^3 x ( -5m^2 + 4n^2 -3n^2 )

<em>keep this parentheses. seriously. </em>

7 0
2 years ago
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