Question

How many grams of iron can be made with 21.5g of Fe2O3

Answer 1

The mass (in grams) of iron, Fe that can be made from 21.5 g of Fe₂O₃ is 15.04 g

We'll begin by writing the balanced equation for the reaction. This is given below:

2Fe₂O₃ -> 4Fe + 3O₂

• Molar mass of Fe₂O₃ = 159.7 g/mol
• Mass of Fe₂O₃ from the balanced equation = 2 × 159.7 = 319.4 g
• Molar mass of Fe = 55.85 g/mol
• Mass of Fe from the balanced equation = 4 × 55.85 = 223.4 g

From the balanced equation above,

319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe

How to determine the mass of iron, Fe produced

From the balanced equation above,

319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe

Therefore,

21.5 g of Fe₂O₃ will decompose to produce = (21.5 × 223.4) / 319.4 = 15.04 g of Fe

Thus, 15.04 g of Fe were produced.

Learn more about stoichiometry:

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