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Bas_tet [7]
2 years ago
8

Write the equation in slope-intercept form of a line that has a slope of and passes through the point (-6, 0). 3. 1 = -2 3. 1 =

3 O y O y=x-6 O y=-x-2 O =+2 1 0 O y=-x+ 2​

Mathematics
1 answer:
Alexus [3.1K]2 years ago
3 0

(\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-6)}) \\\\\\ y=\cfrac{1}{3}(x+6)\implies y=\cfrac{1}{3}x+2

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If (x+2) Is a factor of x^3-6x^2+kx+10<br> k=?
Arlecino [84]

The value of k is -11

Further explanation:

Any number being a factor states that the value of expression will be equal to zero at the factor.

Given

x^3-6x^2+kx+10

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If x=-2 is a factor of given expression then the expression will be zero at x=-2

So.

(-2)^3-6(-2)^2+k(-2)+10 = 0\\-8-6(4)-2k+10 = 0\\-8-24-2k+10 = 0\\-22-2k=0\\-2k=22\\k = -11

The value of k is -11

Keywords: Synthetic division, Factorization

Learn more about synthetic division at:

  • brainly.com/question/5461619
  • brainly.com/question/8280736

#LearnwithBrainly

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almond37 [142]

c.\ f(x)=\dfrac{18}{x}-9\ \text{and}\ g(x)=\dfrac{18}{x+9}\\\\\text{in f(x), solve for x}\\\\\dfrac{18}{x}-9=y\ \ \ \ |+9\\\\\dfrac{18}{x}=y+9\\\\\dfrac{18}{x}=\dfrac{y+9}{1}\ \ \ \ |\text{cross multiply}\\\\x(y+9)=18\ \ \ \ |:(y+9)\\\\x=\dfrac{18}{y+9}\to f^{-1}(x)=\dfrac{18}{x+9}

5 0
3 years ago
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