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aksik [14]
3 years ago
8

A sample of neon gas has a volume of 752 mL at 25.0*. What will the volume be at 100.0*C be if pressure is constant

Chemistry
1 answer:
choli [55]3 years ago
7 0

Answer:941.3mL

Explanation:

V1 = 752mL

T1 = 25°C = 25 +273 = 298K

T2 = 100°C = 100 +273 = 373K

V2 =?

V1/T1 = V2 /T2

752/298 = V2/373

V2 = (752/298) x 373 = 941.3

V2 = 941.3mL

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Explanation:

huh

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A solid mass of 25g is added to a solution with the mass of 60g. The final mass of the solution is 75g. Explain why the mass of
Ann [662]

It is not equal because it dose not obey the conservation of mass. 60+25= 85 not 75.

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4 years ago
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7 0
3 years ago
the air pressure from the atmosphere measures 0.5atm at an altitude of 18,000 ft. How much pressure is this in pounds per square
Julli [10]

14.7lb/in²

Explanation:

This is a conversion problem from atm to pounds per square inch

Pressure is the combined force per unit area of substance on another.

Given pressure = 0.5atm

To solve this problem ;

Convert from atm to N/m² to pound per square inch

    1 atm = 101325N/m²

  0.5atm = 0.5 x 101325 = 50,662.5‬N/m²

now we need to convert to pound per square inch;

     1N  = 0.225lb

     1m = 39.37in

Solving;

 101325 Nx \frac{1}{m^{2} }  x \frac{0.225lb}{1N }  x \frac{m^{2} }{39.37in x 39.37in} = 14.7lb/in²

learn more:

Pressure of gases brainly.com/question/10897667

#learnwithBrainly

8 0
3 years ago
Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between bakin
DanielleElmas [232]

Answer:

74.4 ml

Explanation:

          C₆H₈O₇(aq) + 3NaHCO₃(s) => Na₃C₆H₅O₃(aq + 3CO₂(g) + 3H₂O(l)

Given     15g = 15g/84g/mol = 0.1786mole Sodium Bicarbonate

From equation stoichiometry 3moles NaHCO₃ is needed for each mole citric acid or, moles of citric acid needed is 1/3 of moles sodium bicarbonate used.

Therefore, for complete reaction of 0.1786 mole NaHCO₃ one would need 1/3 of 0.1786 mole citric acid or 0.0595 mole H-citrate.

The question is now what volume of 0.8M H-citrate solution would contain 0.0595mole of the H-citrate? This can be determined from the equation defining molarity. That is => Molarity = moles solute / Liters of solution

=> Volume (Liters) = moles citric acid / Molarity of citric acid solution

=> Volume needed in liters = 0.0.0595 mole/0.80M = 0.0744 Liters or 74.4 ml

6 0
3 years ago
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