2.2Giga
Explanation:
Given that the number of years = 71years
We need to convert this to seconds;
60s = 1 min
60 min = 1hr
24hr = 1 day
7 days = 1 week
52 weeks = 1yr
71 years x
= 2,232,921,600s
This value is 2.2 x 10⁹s = 2.2Giga
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Following reaction is involved in present system:
2KMnO4 + 5H2O2 + 3H2SO4 → 2MnSO4 + K2SO4 + 5O2 + 8H2O
From the above balance reaction, it can be seen that 2 moles of KMnO4 is consumed for every 5 moles of H2O2.
Now, percent by mass of hydrogen peroxide in the original solution can be estimated as follows:
percent by mass =

∴percent by mass =

= 4 %
Answer:
try hypocenter for the blank spot... hope this helps
Explanation:
20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator would be most suitable for this titration? The pKa of CH3CH2NH3+ is 10.75.
Answer:
Bromocresol green, color change from pH = 4.0 to 5.6
Explanation:
The equation for the reaction is as follows:
+
⇄ 
Given that concentration of
= 10%
i.e 10 g of
in 100 ml solution
molar mass = 45.08 g/mol
number of moles = 
= 0.222 mol
Molarity of
= 0.222 × 
= 2.22 M
However, number of moles of
in 20 mL can be determined as:
number of moles of
= 20 mL × 2.22 M
= 
Concentration of
= 
= 2.22 M
Similarly, The pKa Value of
is given as 10.75
pKb value will be: 14 - pKa
= 14 - 10.75
= 3.25
Finally, the pH value at equivalence point is:
pH= ![\frac{1}{2}pKa - \frac{1}{2}pKb-\frac{1}{2}log[C]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DpKa%20-%20%5Cfrac%7B1%7D%7B2%7DpKb-%5Cfrac%7B1%7D%7B2%7Dlog%5BC%5D)
pH = ![\frac{14}{2}-\frac{3.25}{2}-\frac{1}{2}log [2.22]](https://tex.z-dn.net/?f=%5Cfrac%7B14%7D%7B2%7D-%5Cfrac%7B3.25%7D%7B2%7D-%5Cfrac%7B1%7D%7B2%7Dlog%20%5B2.22%5D)
pH = 5.21
∴
The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6.
<h2>
Answer:
</h2>
Explanation:
Let
be the temperature in kelvin.
Let
be the average kinetic energy.
Let
be the number of moles.
Let
be the universal gas constant.
As we know,

Given,

we know that 
So,
=