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kvasek [131]
4 years ago
7

A student collected the above data for this experiment. What error did he make? Explain.

Chemistry
2 answers:
Anvisha [2.4K]4 years ago
8 0
A student collected the above data for this experiment.
He made an error in reporting the correct weight of graduate cylinder with water, as it has to be more than that without water.
anzhelika [568]4 years ago
4 0

Answer:

The mass did not change after adding water, but it should have increased.

The electronic mass balance may not have been tared properly.

The student may have misrecorded data.

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The lifetime of a human is approximately 71 years. Which of the following is this number closest to? Remember the following conv
jarptica [38.1K]

2.2Giga

Explanation:

Given that the number of years = 71years

We need to convert this to seconds;

   60s = 1 min

    60 min = 1hr

   24hr = 1 day

   7 days = 1 week

    52 weeks = 1yr

 71 years x \frac{52weeks }{1yr}  x \frac{7 days}{1 week } x \frac{24hr}{ 1day }  x \frac{60min}{1hr} x \frac{60s}{1min}  = 2,232,921,600‬s

This value is 2.2 x 10⁹s  = 2.2Giga

learn more:

Conversion brainly.com/question/555814

#learnwithBrainly

7 0
3 years ago
A 1.00 g sample of a hydrogen peroxide (H2O2) solution is placed in an Erlenmeyer flask and diluted with 20 mL of 1 M aqueous su
Minchanka [31]
Following reaction is involved in present system:

2KMnO4  +  5H2O2 +  3H2SO4 →  2MnSO4    +     K2SO4  + 5O2  +   8H2O

From the above balance reaction, it can be seen that 2 moles of KMnO4 is consumed for every 5 moles of H2O2.

 Now, percent by mass of hydrogen peroxide in the original solution can be estimated as follows:
percent by mass = \frac{\text{mass of H2O2(g)}}{\text(volume of H2SO4(ml))}X 100
∴percent by mass = \frac{\text{1}}{\text(25)}X 100
                             = 4 % 
5 0
3 years ago
The____of an earthquake is the location where the rupture of an
exis [7]

Answer:

try hypocenter for the blank spot... hope this helps

Explanation:

7 0
3 years ago
20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator
Vinvika [58]

20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator would be most suitable for this titration? The pKa of CH3CH2NH3+ is 10.75.

Answer:

Bromocresol green, color change from pH = 4.0 to  5.6

Explanation:

The equation for the reaction is as follows:

C_2H_5NH_{2(aq)     +     H^+_{(aq)      ⇄        C_2H_5NH_{3(aq)}^+

Given that concentration of C_2H_5NH_{2(aq) = 10%

i.e 10 g of C_2H_5NH_{2(aq) in 100 ml solution

molar mass = 45.08 g/mol

number of moles = \frac{10}{45.08}

= 0.222 mol

Molarity of C_2H_5NH_{2(aq) = 0.222 × \frac{1000}{100}mL

= 2.22 M

However, number of moles of C_2H_5NH_{2(aq) in 20 mL can be determined as:

number of moles of C_2H_5NH_{2(aq) = 20 mL × 2.22 M

= 44*10^{-3} mole

Concentration of C_2H_5NH_{2(aq) = \frac{44*10^{-3}*1000}{20}

= 2.22 M

Similarly, The pKa Value of C_2H_5NH_{2(aq)  is given as 10.75

pKb value will be: 14 - pKa

= 14 - 10.75

= 3.25

Finally, the pH value at equivalence point is:

pH= \frac{1}{2}pKa - \frac{1}{2}pKb-\frac{1}{2}log[C]

pH = \frac{14}{2}-\frac{3.25}{2}-\frac{1}{2}log [2.22]

pH = 5.21

∴

The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6.

6 0
4 years ago
The average kinetic energy of 1 mole of a gas at -32 degrees Celsius is:
Effectus [21]
<h2>Answer:3.01\times 10^{3}J</h2>

Explanation:

Let T be the temperature in kelvin.

Let KE be the average kinetic energy.

Let n be the number of moles.

Let R be the universal gas constant.

As we know,

KE=\dfrac{3}{2}nRT

Given,

n=1\\T=273-32=241K

we know that R=8.314JK^{-1}mol^{-1}

So,KE=\frac{3}{2} \times 1\times 8.314\times 241=3005.5J=3.01\times 10^{3}J

8 0
3 years ago
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