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3 years ago

Label parts of the cell

Chemistry

1 answer:

myrzilka [38]3 years ago

4 0

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An interaction of systems allows for the body to warm itself when it is cold. Which processes help the body warm up when it is c

Dmitry_Shevchenko [17]

Answer:

shivering

hair on the body standing up

goosebump forming

Explanation:

The processes that help the body warm-up from the available options include <em>the shivering of the body</em>, <em>formation of goosebumps on the skin</em>, and <em>the standing up of hairs on the body.</em>

When the temperature of the body falls below the setpoint or the environment is cold, a homeostatic response is triggered and a signal is sent from the control center to the muscles of the body. <u>The muscles start shaking in order to generate heat to raise the temperature of the body</u>. At the same time, <u>the tiny muscles at the base of the hairs on the skin contract and pull the hairs erect, causing goosebumps in the process.</u>

6 0

3 years ago

Read 2 more answers

Please help me, It's my last question :)

Vedmedyk [2.9K]

<h3>Given:</h3>

$V_{1} = \text{5 L}$

$T_{1} = \text{298 K}$

$V_{2} = \text{3 L}$

<h3>Unknown:</h3>

$T_{2}$

<h3>Solution:</h3>

$\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}$

$T_{2} = T_{1} \times \dfrac{V_{2}}{V_{1}}$

$T_{2} = \text{298 K} \times \dfrac{\text{3 L}}{\text{5 L}}$

$\boxed{T_{2} = \text{179 K}}$

$\\$

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3 0

3 years ago

Jose times how long sugar takes to dissolve in warm water. He conducts four trials of his experiment. What should he conclude fr

zloy xaker [14]

Answer:

His experiment has very low precision

Explanation:

Precision is how close the answers are together. The answers are increasing in time. So, this makes sence. None of the answers are similar to one another.

5 0

3 years ago

Gold has a molar mass of 197.0 g/mol. What is the concentration of gold in seawater in moles per liter?(please show work)

natka813 [3]

Answer:

Since you didnt get asked for a spefic weight of gold lets assume it was 5g

Explanation:

5g Au/197 =.02538 mols in 1 liter of sea water is

.02538/1L which gives you a Molarity of .012538 assuming 5g if they ask for a different number just replace 5 with any weight in grams

3 0

3 years ago

The unbalanced equation below shows the combustion of methane.

Ratling [72]

B. 1, 2, 1, 2. You balance the equation by making sure there are equal elements on both sides.

3 0

3 years ago