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Zielflug [23.3K]
3 years ago
5

For which of the following is the shape of the sampling distribution of the sample mean approximately normal? a random sample of

size 5 from a population that is approximately normal a random sample of size 10 from a population that is strongly skewed to the right a random sample of size 60 from a population that is strongly skewed to the left.
Mathematics
1 answer:
RSB [31]3 years ago
6 0

Answer:

a random sample of size 5 from a population that is approximately normal

a random sample of size 60 from a population that is strongly skewed to the left.

Step-by-step explanation:

They are both correct

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A directed line segment on a gridded map shows the path of a hot air balloon from 1(0,0) to B(8,4). Each grid unit represents 1
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Answer:

Step-by-step explanation:

There is  a point V with ration 6 to 2, therefore we must find the coordinates of point V and the distance from A to V

<u>According to the graph</u>

c^{2}=x^{2}+y^{2}\\c^{2}=8^{2}+4^{2}\\c=\sqrt{64+16}=8.9.4\\sin\alpha =\frac{4}{8.94}

α≅27°

V=2*8.94/6 (ratio 6:2)

V=2.98mile

sin27=\frac{y}{2.98}\\y=sin27*2.98=1.35\\cos27=\frac{x}{2.98}\\x=cos27*2.98=2.65

coordinates of V = (2,65;1.35)

Distance from A to V

d_{AV}=2.98 miles

finally

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Combine like terms to create an equivalent expression.<br> -1/2(-3y+10)
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Step-by-step explanation:

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37% of women consider themselves fans of professional baseball. you randomly select six women and ask each if she considers hers
valina [46]

Answer:

(a) 2.22

(b) 1.3986

(c) 1.183

Step-by-step explanation:

Let <em>X</em> denote the number of women who consider themselves fans of professional baseball.

The proportion of women who consider themselves fans of professional baseball is, <em>p</em> = 0.37.

A random sample of <em>n</em> = 6 women are selected and each was asked if she considers herself a fan of professional baseball.

Each woman's reply is independent of the others.

The random variable <em>X</em> thus follows a binomial distribution with parameters <em>n</em> = 6 and <em>p</em> = 0.37.

(a)

Compute the mean of the binomial distribution as follows:

\text{Mean}=np=6\times 0.37=2.22

(b)

Compute the variance of the binomial distribution as follows:

\text{Variance}=np(1-p)=6\times 0.37\times (1-0.37)=1.3986

(c)

Compute the standard deviation of the binomial distribution as follows:

\text{Standard Deviation}=\sqrt{np(1-p)}=\sqrt{6\times 0.37\times (1-0.37)}=1.183

5 0
3 years ago
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