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Vilka [71]
3 years ago
9

F(X)= 2x^2 +1. Find and simplify af(X)+b and f(ax+b)

Mathematics
1 answer:
kati45 [8]3 years ago
8 0
Hello,

f(x)=2x²+1
f(ax+b)=2(ax+b)²+1=2(a²x²+2abx+b²)+1=2a²x²+4abx+2b²+1

af(x)+b=a(2x²+1)+b=2ax²+a+b

And f(ax+b)≠af(x)+b not linear
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sweet-ann [11.9K]

Answer:

h = 40°

Step-by-step explanation:

These 2 angles are congruent due to the Corresponding Angles Theorem.

8 0
3 years ago
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Order from least to greatest<br><br><br> .square root of 2 <br> .pi<br> .4.5
valkas [14]
The way you have it is correct because root 2 is roughly 1.4 pi approximately is 3.4 and 4.5 is a rational number
8 0
3 years ago
Help need pls anewer 1-4​
Art [367]

Answer:

1. width is w. length is w + 26

2.

w \times (w  + 26)   < 2040

3. the width must be less than 34

4. sure, if the width is 10, then the area is 360

Step-by-step explanation:

w \times (w  + 26)   < 2040

1

7 0
2 years ago
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A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each
Nadya [2.5K]

Answer:

312.5\pi \text{ km}^3\approx 981.75\text{ km}^3

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}, where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3

Therefore, the volume of earth removed to build the three tunnels is 312.5\pi \text{ km}^3\approx 981.75\text{ km}^3.


4 0
3 years ago
Find the volume of the cylinder.<br> Either enter an exact answer in terms of π or use 3.14 for π
Alex787 [66]

Answer:

Volume of the cylinder = 62.80 units^3

Step-by-step explanation:

Height of the Cylinder(h)=5 units

Radius(r)=2 units

Volume of a cylinder=\pi *r*r*h

     Putting the values in the formula;

Volume of the cylinder =\pi *2*2*5

                      As,   \pi =\frac{22}{7}=3.14                        

Volume of the cylinder=  3.14*2*2*5

                                 =3.14*2*2*5\\\\=3.14*4*5\\\\=3.14*20\\\\=62.80units^3                              

The Volume of the cylinder is 62.80 units^3

7 0
3 years ago
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