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Alla [95]
2 years ago
13

Please help me quick

Mathematics
1 answer:
snow_tiger [21]2 years ago
6 0
I believe it should be twelve (Brainliest please)
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A home builder wants 5 acres of land split into 13 equal sections. Three of these expressions give the number of acres of land e
galina1969 [7]

Answer:

b 5/13

Step-by-step explanation:

6 0
4 years ago
1. A right circular cylinder has a height of 5 in. and a base area of 20 in2. What is the volume of the cylinder? Use π = 3.14.
Kruka [31]

Answer:

<h2>1. V = 100 in³</h2><h2>2. h = 10 in</h2>

Step-by-step explanation:

The formula of a volume of a cylinder:

V=Bh

<em>B</em><em> - base area</em>

<em>h</em><em> - height</em>

<em />

1. We have

<em>h = 5in, B = 20 in²</em>.

Substitute:

V=(5)(20)=100\ in^3

2. We have

<em>B = 20.7 in², V = 207 in³</em>.

Substitute:

207=20.7h            <em>divide both sides by 20.7</em>

\dfrac{207}{20.7}=\dfrac{20.7h}{20.7}\\\\10=h\to h=10\ in

4 0
3 years ago
Read 2 more answers
PLEASE HELP I HAVE 3 MINS LEFT FAST!!!! ILL MARK BRAINLIEST!!!
GenaCL600 [577]
A-1500
B-1500
C-1500+1500=3000
7 0
3 years ago
A picture of a school’s mascot is 18 in. wide and 24 in. long. It is enlarged proportionally to banner size. If the width is enl
Vesna [10]
18/24 = 63/x...18 width to 24 length = 63 width to x length
cross multiply
(18)(x) = (24)(63)
18x = 1512
x = 1512/18
x = 84 inches <===
8 0
3 years ago
Can someone please please help me
velikii [3]

Answer:

  order: 2, 3, 1

Step-by-step explanation:

Reasonableness checks and your knowledge of integers and fractions will help you solve this. The offered questions are intended to help you think this through.

<h3>a.</h3>

For an output of -31, the machine (x -2)² cannot possibly be last. Its output can only be positive.

  machine 2, (x-2)², cannot be last

Also, machine 3 cannot be last. For the output to be -31, the input to machine 3 must be -1/31. Neither of the other machines can produce a fraction with the inputs they might receive.

<h3>b.</h3>

For an input of x=0, the machine 1/x cannot possibly be first. 1/0 is undefined.

The other two machines will give the following outputs for an input of 0:

  machine 1: 4(0) -32 = -32

  machine 2: (0 -2)² = 4

It is unlikely that machine 1 will be first, because the other two machines cannot do anything useful with -32 as an input.

  machine 3, 1/x, cannot be first

<h3>c.</h3>

The reasoning of part (a) tells you the last machine must be machine 1. The reasoning of part (b) tells you the first machine cannot be 3, so must be 2. The order of the machines must be ...

  • machine 2: (0 -2)² = 4 . . . . . . . using an input of 0
  • machine 3: 1/4 = 1/4
  • machine 1: 4(1/4) -32 = -31 . . . . desired output
7 0
2 years ago
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