Energy is neither created nor destroyed; when energy is transformed from one form to another, there is no energy lost
Answer:
maximum speed of the block is 3.14 m/s
Explanation:
given data
mass = 1.70 kg
stretch in the spring = 0.2 m
time take by block to come to zero t = 0.2 s
solution
we know that Time period of oscillation (T) that is express as
T = 2t ......................1
put here value
T = 2 (0.2)
T = 0.4 s
so here time period is express as
T = 
................2
here k is spring constant of the spring so put here value
0.4 = 
here k will be
k = 419.02 N/m
so we use here conservation of energy that is
Maximum kinetic energy = Maximum spring potential energy ............3
(0.5) m v² = (0.5) k x²
here v is maximum speed block
so put here value and we get
(1.70) v² = (419.02) (0.2)²
v = 3.14 m/s
so maximum speed of the block is 3.14 m/s
Answer: 1.6m/s
Explanation:
M1 = 13500kg
U1 = 4.5m/s
M2 = 25000kg
U2 = 0m/s (since the body is at rest)
V = ? (Common velocity or velocity after impact)
M1U1 + M2U2 = (M1 + M2)V
But U2 = 0
M1U1 = (M1 + M2)V
13500 * 4.5 = (13500 + 25000)v
60750 = 38500v
V = 60750 / 38500 = 1.5779 = 1.6m/s
Answer:
0.546 ohm / μm
Explanation:
Given that :
N = 1.015 * 10^17
Electron mobility, u = 3900
Hole mobility, h = 1900
Ng = 4.42 x10^22
q = 1.6*10^-19
Resistivity = 1/qNu
Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)
= 0.01578880889 ohm /cm
Resistivity of germanium :
R = 1 / 2q * sqrt(Ng) * sqrt(u*h)
R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)
R = 1 /0.0001831
R = 5461.4964 ohm /cm
5461.4964 / 10000
0.546 ohm / μm
' +4 m/s² ' means that the pigeon's speed is 4 m/s greater every second.
Starting from zero speed, after 10 seconds, its speed is
(10 x 4m/s) = 40 m/s.
We can't say anything about its velocity, because we have
no information regarding the direction of its flight.
