Answer:
length of a quarter wavelength antenna for transmitter elf waves are zero
Explanation:
Find the length of a quarter wavelength antenna for transmitter elf waves
Given information
frequency (ELF waves) → 77Hz
Speed of light → 3
m/s
where
→ wavelength of the antenna
f → frequency of the ELF waves
→ speed of light
so rewrite the equation in 
from
Substitute 
=
Substitute 75Hz = f
m
since we get this value,but this size of antenna mount on submarine is not possible.
so is zero
Answer:
A) 50 seconds
B) 200 m
Explanation:
They are 500 metres apart.
And one of the bike loves at 6 m/s while the other loves at 4 m/s.
A) Let distance of the 6 m/s bike before they meet be x.
Thus, time = x/6
Since time = distance/speed
For the second bike at 4 m/s, his distance covered before they meet will be 500 - x
Thus, time = (500 - x)/4
Now they will meet each other at the same time. Thus;
x/6 = (500 - x)/4
Cross multiply to get;
4x = 3000 - 6x
6x + 4x = 3000
10x = 3000
x = 3000/10
x = 300 m
Thus, time will be;
t = 300/6
t = 50 seconds
B) Distance covered by the slower bike is (500 - x)
Since from a above, x = 300
Thus; distance = 500 - 300 = 200 m
Crafting, reusing
Good luck!
Answer:
The difference in the decibel corresponses to a constant difference in the loudness perceived.
The refore the sound intensity from the orchestra is like 100 times that of the violin.
Explanation:
30 grams because of conservation
