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3 years ago

10

How do particles move differently in transverse waves and in surface water waves?

1 answer:

elixir [45]3 years ago

3 0

The particles always move parallel and perpendicular to the waves. The waves which are in the water moves a circle. Both up and down and back and forth.

Good luck :)

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It was a children versus grown-ups competition at school. One event required the adult to throw a basketball as far as he could.

aleksklad [387]

Based on Newton's Law, the event is not fair because:

<span>No, because a basketball is bigger than a baseball, and objects that are bigger accelerate slower.

I hope my answer has come to your help. God bless and have a nice day ahead!</span>

4 0

3 years ago

Read 2 more answers

Critics of the electoral college argue that the system can result in the selection of —

Romashka [77]

Answer:

President who did not win the popular vote

Explanation:

Critics of the Electoral college argue that the system can result in a selection of what?

6 0

3 years ago

What is the acceleration of a 349 kg object that moved with a force of 750 N?

zavuch27 [327]

Answer:

<h3>The answer is 2.15 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

where

f is the force

m is the mass

From the question we have

$a = \frac{750}{349} \\ = 2.14899713...$

We have the final answer as

<h3>2.15 m/s²</h3>

Hope this helps you

4 0

3 years ago

How much heat is necessary to warm 500g of water from 20°c to 65°c

Vsevolod [243]

Explanation:

so sorry

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8 0

3 years ago

A fast-food restaurant uses a conveyor belt to send the burgers through a grilling machine. if the grilling machine is 1.2 m lon

Vinil7 [7]

length of the grilling machine is 1.2 m

time taken to cook the burger is 2.7 min = 162 s

so the speed of the machine should be like this that if must have to cook till it cross the machine

$v = \frac{d}{t}$

$v = \frac{1.2}{162}$

$v = 7.41* 10^{-3} m/s$

now in one minute the total length of the machine that is covered is given by

$L = v*t$

$L = 7.41*10^{-3}* 60 = 44.4 cm$

now distance between the burgers is 15 cm

so total production rate will be

$N = \frac{44.4}{15} = 3 burger/min$

so it will produce 3 burger per minute

8 0

3 years ago