The large van has 23 seats and the small van has 17 seats
Answer:
500 kilometers
Step-by-step explanation:
The fuel (y) Karl has in his car is a function of the distance (x) Karl travelled. The amount of fuel (y) is dependent on the distance (x) Karl travelled.
On the y-axis, we have amount of fuel.
On the x-axis, we have distance travelled.
At the time Karl travelled when he had 200 liters of fuel (y) remaining in his car, he had travelled a distance (x) of 500 kilometers.
We know this by looking at the graph given. When x (distance) = 500, y (fuel) = 200.
Answer:
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
The margin of error of the interval is given by:
![M = z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In this problem, we have that:
![p = 0.69](https://tex.z-dn.net/?f=p%20%3D%200.69)
99.5% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?
This is n when M = 0.07. So
![M = z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
![0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}](https://tex.z-dn.net/?f=0.07%20%3D%202.81%5Csqrt%7B%5Cfrac%7B0.69%2A0.31%7D%7Bn%7D%7D)
![0.07\sqrt{n} = 1.2996](https://tex.z-dn.net/?f=0.07%5Csqrt%7Bn%7D%20%3D%201.2996)
![\sqrt{n} = \frac{1.2996}{0.07}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%20%5Cfrac%7B1.2996%7D%7B0.07%7D)
![\sqrt{n} = 18.5658](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%2018.5658)
![(\sqrt{n})^{2} = (18.5658)^{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E%7B2%7D%20%3D%20%2818.5658%29%5E%7B2%7D)
![n = 345](https://tex.z-dn.net/?f=n%20%3D%20345)
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Ddcvv was a great night for you guys I love ya too
10unites square
hope this helps
btw make me brainliest?