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marusya05 [52]
3 years ago
15

What axis does the independent quantity go on?

Mathematics
1 answer:
Contact [7]3 years ago
5 0
Horizontal
The Axes. The independent variable belongs on the x-axis (horizontal line) of the graph and the dependent variable belongs on the y-axis
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Complete the solution of the equation find the value of y when x equals 2. -8x - 5y = -1
tatuchka [14]

Answer: y = -3

<u>Step-by-step explanation:</u>

-8x - 5y = -1

<u>+8x        </u>  <u>+8x </u>

       -5y = 8x  - 1

       <u> ÷-5 </u> <u> ÷-5</u>  <u>÷-5</u>

           y = -\frac{8}{5}x + \frac{1}{5}

       y(2) = -\frac{8}{5}(2) + \frac{1}{5}

               = -\frac{16}{5} + \frac{1}{5}

               = -\frac{15}{5}

                = -3

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4 years ago
What is 1/12x(4+6x3)-9?
sertanlavr [38]
Your answer is -43/6

1/12(4+6x3)-9
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3 years ago
What is the volume of the cylinder shown below?
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<em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>it </em><em>is </em><em>given </em><em>that</em><em>. </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>height</em><em> </em><em>of </em><em>cylinder</em><em> </em><em>=</em><em> </em><em>1</em><em>5</em><em>u</em><em>n</em><em>i</em><em>t</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>radius</em><em> </em><em>of</em><em> </em><em>base </em><em>=</em><em> </em><em>9</em><em>u</em><em>n</em><em>i</em><em>t</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>volume</em><em> of</em><em> </em><em>cylinder</em><em> </em><em>=</em><em> </em><em>π </em><em>r^</em><em>2</em><em>h</em><em> </em><em>cubic </em><em>unit</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>now,</em><em> </em><em>putting</em><em> the</em><em> value</em><em> of</em><em> </em><em>height</em><em> and</em><em> </em><em>radius </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>in </em><em>above </em><em>formula </em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>2</em><em>2</em><em>/</em><em>7</em><em> </em><em>*</em><em>9</em><em>*</em><em>9</em><em>*</em><em>1</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>3</em><em>6</em><em>1</em><em>7</em><em>7</em><em>c</em><em>u</em><em>b</em><em>i</em><em>c</em><em> </em><em>unit</em>

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