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3 years ago

What axis does the independent quantity go on?

1 answer:

5 0

Horizontal
The Axes. The independent variable belongs on the x-axis (horizontal line) of the graph and the dependent variable belongs on the y-axis

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Answer I'll give brainliest to first one<br>10 points

defon

Answer:

Have a splendiferous day...

Step-by-step explanation:

3÷12=¼

6÷10=⅗

7÷14=½

10÷11=⅚

2÷4=½

4÷16=¼

3÷24=⅛

18÷54=⅓

7 0

2 years ago

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Exg(x), where g(0) = 6 and g'(0) = 1, find f '(0).

Phantasy [73]

Your answer is h (20’mm) x^c’’

6 0

2 years ago

3-4y=5x-6. The answer is (-5x^4-9)/4. Please explain how to get this.

xenn [34]

Answer:

The direction of mathematics teacher is study about the mathematics teacher is study about it is by step instructions

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1 year ago

Write 2/3 as a decimal.

Mekhanik [1.2K]

Answer:

0.67

Step-by-step explanation:

2/3 = 0.6666

0.6666 rounded to the nearest hundredth = 0.67

3 0

3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

3 years ago

Read 2 more answers