V=(1/3)hpir^2
v=130
h=13
r=x
130=(1/3)(13)pix^2
times both sides by 3
390=13pix^2
divide both sides by 13
30=pix^2
divide both sides by pi
30/pi=x^2
sqrt both sides
x≈3.09
radius is abou 3 units
Because the vertex of the parabola is at (16,0), its equation is of the formy = a(x-10)² + 15
The graph goes through (0,0), thereforea(0 - 10)² + 15 = 0100a = -15a = -0.15
The equation is y = f(x) = -0.15(x - 10)² + 15
The graph is shown below.
Part A
Note that y = f(x).
The x-intercepts identify values where the function or y=0. The x-intercepts occur at x=0 and x=20, or at (0,0) and (20,0).
The maximum value of y occurs at the vertex (10, 15) because the curve is down due to the negative leading coefficient of -0.15.
The curve increases in the interval x = (-∞, 10) and it decreases in the interval x = (10, ∞).
Part B
When x=12, y = -0.15(12 - 10)² + 15 = 14.4When x=15, y = -0.15(15 - 10)² + 15 = 11.25
The average rate of change between x =12 to x = 15 is(11.25 - 14.4)/(15 - 12) = -1.05
This rate of change represents the slope of the secant line from A to B. It approximates the rate at which f(x) decreases in the interval x =[12, 15].
Answer:
50.27 units²
Step-by-step explanation:²
The standard equation of a circle with center at the origin is x² + y² = r², where r is the radius. Substituting 4 for x and 0 for y yields 4² + 0² = r², so we see immediately that r = 4 units.
The formula for the area of a circle is A = πr².
Here, with r = 4, the area is A = π(4 units)² = 16π units², or
50.27 units² to the nearest hundredth.
Answer:
0.052 acre/min
Step-by-step explanation:
6 1/4 acres / 2 hours times the conversion factor (1 hr / 60 min) comes out to:
6.25
----------------- = 0.052 acre/min
2 (60 min)
---------
Answer:
<em>Grades to be scored in 3rd exam = 88</em>
Step-by-step explanation:
Given that average of 3 numbers is 85.
First two numbers are 81 and 86.
To find:
3rd number so that average is 85
Solution:
Let the third number = 
Formula for average is:
Here, sum of numbers = 
Total count of numbers = 3
<em>Grades to be scored in 3rd exam = 88</em>
