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The answer would be (1,3)
We know that
if cos x is positive
and
sin x is negative
so
the angle x belong to the IV quadrant
cos x=5/13
we know that
sin²x+cos²x=1-------> sin²x=1-cos²x------> 1-(5/13)²---> 144/169
sin x=√(144/169)-------> sin x=12/13
but remember that x is on the IV quadrant
so
sin x=-12/13
Part A) <span>cos (x/2)
cos (x/2)=(+/-)</span>√[(1+cos x)/2]
cos (x/2)=(+/-)√[(1+5/13)/2]
cos (x/2)=(+/-)√[(18/13)/2]
cos (x/2)=(+/-)√[36/13]
cos (x/2)=(+/-)6/√13-------> cos (x/2)=(+/-)6√13/13
the angle (x/2) belong to the II quadrant
so
cos (x/2)=-6√√13/13
the answer Part A) is
cos (x/2)=-6√√13/13
Part B) sin (2x)
sin (2x)=2*sin x* cos x------> 2*[-12/13]*[5/13]----> -120/169
the answer Part B) is
sin(2x)=-120/169
Answer:
a) Upwards
b) x = -1
c) (-1,-9)
d) x intercepts; (2,0) and (-4,0)
y intercept is (0,-8)
Step-by-step explanation:
a) As we can see, the parabola faces upwards
b) To find the axis of symmetry equation, we look at the plot of the graph and see the point through the vertex of the parabola that exactly divides the parabola into two equal parts
The x-value that the line passes through here is the point x = -1 and that is the equation of the axis of symmetry
c) The vertex represents the lowest point of the circle here,
As we can see, this is the point through which the axis of symmetry passes through to make a symmetrical division of the parabola
We have the coordinates of this point as
(-1,-9)
d) The intercepts
The x-intercept are the two points in which the parabola crosses the x-axis
We have this point as 2 and -4
The x-intercepts are at the points (2,0) and (-4,0)
For the y-intercept; it is the y-coordinate of the point at which the parabola crosses the y-axis and this is the point (0,-8)
