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2 years ago

Help (๑¯◡¯๑)me please

Physics

2 answers:

Allushta [10]2 years ago

4 0

Answer:

<h3>Young modulus of elasticity for a gas is</h3><h2>Zero</h2>

Explanation:

As the gas doesn't undergo any changes 

so the young modules of gas is not defined...

leonid [27]2 years ago

3 0

We know

$\\ \rm\hookrightarrow Y=\dfrac{Stress}{Strain}$

$\\ \rm\hookrightarrow Y=\dfrac{\sigma}{\Delta \ell/\ell}$

Stress is zero

$\\ \rm\hookrightarrow Y=\dfrac{0}{\Delta \ell/\ell}$

$\\ \rm\hookrightarrow Y=0$

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If an item as a density of.63 g/mL, when placed in water the item will

sergij07 [2.7K]

Float. This is because water has a density of 1 g/ml, so anything less than this will float.

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4 years ago

Phenolphthalein turns pink in salt water

OLEGan [10]

That statement is true

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3 years ago

Introduction Team Problem 2 You jump into the deep end of Legion Pool and swim to the bottom with a pressure gauge. The gauge at

Kaylis [27]

Answer:

Depth of the pool, h = 4.004 cm

Explanation:

Pressure at the bottom, P = 39240 N/m²

The density of water, d = 1000 kg/m³

The pressure at the bottom is given by :

P = dgh

We need to find the depth of pool. Let h is the depth of the pool. So,

$h=\dfrac{P}{dg}$

$h=\dfrac{39240\ N/m^2}{1000\ kg/m^3\times 9.8\ m/s^2}$

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So, the pool is 4.004 meters pool. Hence, this is the required solution.

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4 years ago

A 800 J B -800 J C 400 J D -400 J ??

Ierofanga [76]

I think it will be 800j because right absorb mean getting more

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4 years ago

Froghopper insects have a typical mass of around 11.3 mg and can jump to a height of 58.8 cm. The takeoff velocity is achieved a

allochka39001 [22]

Answer:

2874.33 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{v^2-0^2}{2\times h}\\\Rightarrow v^2=2ah\ m/s$

Now H-h = 0.588 - 0.002 = 0.586 m

The final velocity will be the initial velocity

$v^2-u^2=2as\\\Rightarrow 0^2-u^2=2gs\\\Rightarrow -2ah=2\times g(H-h)\\\Rightarrow -2a0.002=2\times g0.586\\\Rightarrow a=-\frac{0.586\times -9.81}{0.002}\\\Rightarrow a=2874.33\ m/s^2$

Acceleration of the frog is 2874.33 m/s²

6 0

4 years ago

Help (๑¯◡¯๑)me please ​

Help (๑¯◡¯๑)me please