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mart [117]
3 years ago
15

You are an evolutionary biologist studying a population of bats in the rain forest in Brazil. Most of the population possesses m

oderate length wings, although some individuals have long wings and some individuals have short wings. Over the course of time, you notice that the frequency of moderate-length wings increases. You conclude that the most likely cause of this development is:
a. diversifying natural selection
b. stabilizing natural selection.
c. directional natural selection.
d. co-evolution.
Physics
1 answer:
Oxana [17]3 years ago
3 0

Answer:

Option (B)

Explanation:

In the stabilizing natural selection, the extreme traits from both the ends are eliminated by natural selection and natural selection favors the intermediate trait. So over time individuals having the intermediate traits are selected over the individuals having extreme traits.

So here the population of the bat which possesses moderate wing length is selected over the individual with extreme traits like individuals with short wings and long wings. As a result, the population of moderate length wing bats increased.

Therefore the correct answer is (B)- stabilizing natural selection.

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A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes
Ludmilka [50]

Answer:

Force applied to stop the car = 1,250 N

Explanation:

Given:

Mass of car (M) = 1,000 kg

Initial velocity (U) = 20 m/s

Final velocity (V) = 0 m/s

Distance (S) = 160 m

Find:

Force applied to stop the car.

Computation:

v^2 = u^2 + 2as\\\\0^2=20^2+2(a)(160)\\\\0=400+320(a)\\\\Acceleration = a = -1.25m/s^2\\\\Force = ma \\\\Force= 1,000(1.25)\\\\Force = 1,250 N

Force applied to stop the car = 1,250 N

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2 years ago
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Answer:

Option A - twice

Explanation:

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3 years ago
Will a series circuit work if there are two batteries and one light bulb? Help asappp please!
Dmitry_Shevchenko [17]

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2 years ago
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Several large firecrackers are inserted into the holes of a bowling ball, and the 6.3 kg ball is then launched into the air with
Anni [7]

Answer

given,

mass of the ball = 6.3 kg

speed of the ball = 10.4 m/s

angle made with horizontal = 43°

m_a = 1.8 kg               v_a = 2.2 m/s

m_b = 1.6 kg               v_b = 1.8 m/s

mass of third particle = 6.3 - 1.8 - 1.6

                                   = 2.9 kg

u cos θ = 10.4 x cos 43° = 7.61 m/s

by using conservation momentum along x-axis

6.3 x 7.61 = 1.8 × (-2.2) + 0 + 1.6 × V₃ₓ

V₃ₓ = 32.44 m/s (toward right)

by using conservation momentum along y-axis

0 = 0 + 1.6 x 1.8 + 1.6 × V₃y

V₃y = -1.8 m/s (indicate downward)

velocity of the third particle

v = \sqrt{32.44^2 + (-1.8)^2}

v = 32.49 m/s

tan \theta = \dfrac{-1.8}{32.44}

\theta = tan^{-1}(\dfrac{-1.8}{32.44})

θ = 3.176° (downward with horizontal)

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